No, they forgot to switch variable labels after solving for the independent variable...
y=-8x+4
y-4=-8x
(y-4)/-8=x
Now that you have solved for the independent variable x, you switch the variable labels...
y=(x-4)/-8
f^-1(x)=(x-4)/-8 which should really be rewritten as:
f^-1(x)=(4-x)/8 :P
Answer:
Step-by-step explanation:
Here's how you convert:
The little number outside the radical, called the index, serves as the denominator in the rational power, and the power on the x inside the radical serves as the numerator in the rational power on the x.
A couple of examples:
![\sqrt[3]{x^4}=x^{\frac{4}{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E4%7D%3Dx%5E%7B%5Cfrac%7B4%7D%7B3%7D)
![\sqrt[5]{x^7}=x^{\frac{7}{5}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%5E7%7D%3Dx%5E%7B%5Cfrac%7B7%7D%7B5%7D)
It's that simple. For your problem in particular:
is the exact same thing as ![\sqrt[3]{7^1}=7^{\frac{1}{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B7%5E1%7D%3D7%5E%7B%5Cfrac%7B1%7D%7B3%7D)
Answer:
7/2
Step-by-step explanation:
3 wholes is equal to 6 halves plus a half equals 7 halves
Answer:
The expression that uses the distributive property to represent the sum of 39 + 27 is 
Step-by-step explanation:
Given
Expression: 39 + 27
Required
Express using the distributive property
The distributive property is represented in the form a(b + c)
So, we can say that the meaning to the question is that the given expression should be represented in the form a(b+c)
Equate these two expressions, we have

Factorize the expression on the left hand side

Simplify fraction

Compare expression on left hand side with the expression on the right hand side.
Since, they have the same format, then we've arrived at the answer.
Hence, the expression that uses the distributive property to represent the sum of 39 + 27 is 
Answer:
720
Step-by-step explanation:
I will use the following counting principle:
Product rule: if there are n ways of doing something, and m ways of doing another thing, there are n×m ways of doing both things.
First, we have to choose the 3 people that will be in the first row. This is a 3-element subset of the set of six people, therefore there are
ways of doing this.
Now, we have to arrange the order of the 2 lrows. Each one has 3 people, so there are 3!=6 ways to form one rows. Hence, there are 3!²=36 ways of arranging the two rows.
By the product rule, there are 20×36=720 ways of arrange the officers.