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olga55 [171]
3 years ago
10

PLEASE HELPPP ASAPPPPP

Mathematics
2 answers:
nika2105 [10]3 years ago
5 0

Answer:

combination  91 ways

Step-by-step explanation:

This is a combination since order doesn't matter

Permutation are when order matter

14 choose 2 order doesnt matter

14*13

--------

2*1

91 different ways

Liono4ka [1.6K]3 years ago
3 0
The answer is permutation !
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Answer:

The values for expression is h = - 2 and k = 5

Step-by-step explanation:

Given algebraic expression can be written as :

2 x³ - 10 x² + 11 x - 7 = ( x - 4 ) × ( 2 x² + h x + 3 ) + k

Now opening the bracket

Or, 2 x³ - 10 x² + 11 x - 7 = x × ( 2 x² + h x + 3 ) - 4 × ( 2 x² + h x + 3  ) + k

Or, 2 x³ - 10 x² + 11 x - 7 = 2 x³ + h x² + 3 x - 2 x² - 4 h x - 12  +k

Or , 2 x³ - 10 x² + 11 x - 7 = 2 x³ + ( h - 2 ) x² + ( 3 - 4 h ) x - 12  + k

Now, equating the equation both sides

I.e  - 10 =  ( h - 2 )

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I.e , h = - 10 + 2

∴ h = - 2

Again , 11  = ( 3 - 4 h )

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or, 8 = - 4 h

∴ h = \frac{-8}{4}

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Again

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∴  k = 5

Hence The values for expression is h = - 2 and k = 5    . Answer

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Let the even E be: getting an even number. The successful outcomes set is  E {2, 4, 6 } and n(E)=3

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