Is this correct??????

Mathematics

1 answer:

Kay [80]3 years ago

8 0

Yes it is correct I’m pretty sure

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If u(x)=-2x²+3 and v(x)=1/x, what is the range of (u ° v)(x)?

Ludmilka [50]

$u(x)=-2x^2+3\\\\v(x)=\dfrac{1}{x}\\\\(u\ \circ\ v)(x)=-2\left(\dfrac{1}{x}\right)^2+3=-2\left(\dfrac{1}{x^2}\right)+3=-\dfrac{1}{x^2}+3\\\\\text{The range of}\ y=\dfrac{1}{x^2}\ \text{is all positive real numbers.}\\\\\text{The range of}\ y=-\dfrac{1}{x^2}\ \text{is all negative real numbers.}\\\\\text{The range of }\ (u\ \circ\ v)(x)=-\dfrac{1}{x^2}+3\ is\ (-\infty,\ 3)$

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4 years ago

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Which of these transformations are isometries?

yulyashka [42]

Answer:
I, II and III.

Explanation:
An isometry is a transformation that preserves the size of the pre-image in the image and the corresponding angles and sides are also congruent.

In each one of the images, the figure given is he same size as the pre-image and The corresponding angles and corresponding sides are congruent; therefore they are all isometries.

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3 years ago

Find the slope of the Line A -1/2 B 2 C -2 D 1/2

never [62]

Answer:

-1/2

Step-by-step explanation:

(0,1) , (2,0)

$\frac{y2-y1}{x2-x1} = \frac{0-1}{2-0} = \frac{-1}{2}$