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PIT_PIT [208]
3 years ago
11

Rectangle ABCD is similar to rectangle QRST. The width of ABCD is 5 inches and the length is 8 inches. If the length of QRST is

12 inches, what is the width of QRST?

Mathematics
1 answer:
omeli [17]3 years ago
8 0
Answer: 7.5

Form your proportion. Let x be the width of QRST.

Length of ABCD      Length of QRST
-----------------------  =  ------------------------- 
Width of ABCD         Width of QRST

8/5 = 12/x

Solve for x by cross-multiplying.
(8)(x) = (12)(5)
8x = 60
x = 7.5


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Solve the system of equations by graphing where f(x)=5-2x and g(x)=(2/3)x-2. What is the value of x? 0 1 2 3 4
vfiekz [6]

Answer:

The graph is uploaded in the attachment.

The value of x is 2.625.

Step-by-step explanation:

  • let us plot f(x), g(x) on y-axis

so, f(x)=y and g(x)=y.

  • the first equation can be written as y=5-2x
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( where m is the slope and c is the y-intercept )

  • now comparing given equation with the general equation mentioned above, the slope of first line is -2 and its y-intercept is 5
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  • now plot the graph using above information.

(y-intercept is the the coordinate of a point where the line intersects y-axis)

(slope is the angle made by the line with the x-axis)

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3 0
3 years ago
Recent census data indicated that 14.2% of adults between the ages of 25 and 34 live with their parents. A random sample of 125
kicyunya [14]

Answer:

The  probability is  P(14 <  X  <  20 ) =  0.5354  

Step-by-step explanation:

From the question we are told that

   The  proportion that live with their parents is  \r p  =  0.142

   The  sample  size is n =  125

   

Given that there are two possible outcomes and that this outcomes are independent of each other then we can say the Recent census data follows a Binomial distribution

  i.e  

       X   \  \~ \ B( \mu ,  \sigma )

Now the mean is evaluated as

      \mu  =  n *  \r p

      \mu  =  125 *  0.142

      \mu  =  17.75

Generally the proportion that are not staying with parents is  

      \r  q  =  1 -  \r  p

= >    \r  q  =  0.858

The standard deviation is mathematically evaluated as

     \sigma  =  \sqrt{n * \r p  *  \r q }

     \sigma  =  \sqrt{ 125 *  0.142 * 0.858  }

    \sigma  = 3.90

Given the n is large  then we can use normal approximation to evaluate the probability as follows  

     P(14 <  X  <  20 ) =  P( \frac{ 14 -  17.75}{3.90}

Now applying continuity correction

      P(14 <  X  <  20 ) =  P( \frac{ 13.5 -  17.75}{3.90}  < \frac{  X  - \mu }{\sigma } < \frac{ 19.5 -  17.75}{3.90}   )

Generally  

    \frac{  X  - \mu }{\sigma }  =  Z  ( The  \ standardized \ value  \  of  X )

    P(14 <  X  <  20 ) =  P( \frac{ 13.5 -  17.75}{3.90}  < Z< \frac{ 19.5 -  17.75}{3.90}   )

     P(14 <  X  <  20 ) =  P( -1.0897   < Z<  0.449 }   )

    P(14 <  X  <  20 ) =   P( Z<  0.449   ) - P(Z  <   -1.0897)

So  for the z -  table  

         P( Z<  0.449   ) =  0.67328

         P(Z  <   -1.0897)  = 0.13792

 P(14 <  X  <  20 ) =   0.67328 -  0.13792    

  P(14 <  X  <  20 ) =  0.5354  

     

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