If you rotated the box 90º, the orrientation would not be the same, so it is not D or B.
After rotating 180º, the box will be in the 1st quadrant. If it moved along the x-axis, it wouldnt be there anymore, and the after-picture shows it in the first quadrant still, so the only answer it can be is C.
How to solve your problem
Topics: Algebra
−
1
2
3
⋅
(
−
8
+
(
−
4
)
−
6
)
+
2
−
12
3
⋅
x
(
−
8
+
(
−
4
)
−
6
)
+
2
3−12⋅x(−8+(−4)−6)+2
Simplify
1
Divide the numbers
−
1
2
3
⋅
(
−
8
+
(
−
4
)
−
6
)
+
2
−
12
3
⋅
x
(
−
8
+
(
−
4
)
−
6
)
+
2
3−12⋅x(−8+(−4)−6)+2
−
4
(
−
8
+
(
−
4
)
−
6
)
+
2
−
4
x
(
−
8
+
(
−
4
)
−
6
)
+
2
−4x(−8+(−4)−6)+2
2
Evaluate the exponent
−
4
(
−
8
+
(
−
4
)
−
6
)
+
2
−
4
x
(
−
8
+
(
−
4
)
−
6
)
+
2
−4x(−8+(−4)−6)+2
−
4
(
−
8
+
1
4
0
9
6
)
+
2
−
4
x
(
−
8
+
1
4096
)
+
2
−4x(−8+40961)+2
3
Add the numbers
−
4
(
−
8
+
1
4
0
9
6
)
+
2
−
4
x
(
−
8
+
1
4096
)
+
2
−4x(−8+40961)+2
−
4
(
−
3
2
7
6
7
4
0
9
6
)
+
2
−
4
x
(
−
32767
4096
)
+
2
−4x(−409632767)+2
4
Multiply the numbers
−
4
(
−
3
2
7
6
7
4
0
9
6
)
+
2
−
4
x
(
−
32767
4096
)
+
2
−4x(−409632767)+2
3
2
7
6
7
1
0
2
4
+
2
32767
1024
x
+
2
102432767x+2
5
Combine multiplied terms into a single fraction
3
2
7
6
7
1
0
2
4
+
2
32767
1024
x
+
2
102432767x+2
3
2
7
6
7
1
0
2
4
+
2
32767
x
1024
+
2
102432767x+2
6
Find common denominator
3
2
7
6
7
1
0
2
4
+
2
32767
x
1024
+
2
102432767x+2
3
2
7
6
7
1
0
2
4
+
1
0
2
4
⋅
2
1
0
2
4
32767
x
1024
+
1024
⋅
2
1024
102432767x+10241024⋅2
7
Combine fractions with common denominator
3
2
7
6
7
1
0
2
4
+
1
0
2
4
⋅
2
1
0
2
4
32767
x
1024
+
1024
⋅
2
1024
102432767x+10241024⋅2
3
2
7
6
7
+
1
0
2
4
⋅
2
1
0
2
4
32767
x
+
1024
⋅
2
1024
102432767x+1024⋅2
8
Multiply the numbers
3
2
7
6
7
+
1
0
2
4
⋅
2
1
0
2
4
32767
x
+
1024
⋅
2
1024
102432767x+1024⋅2
3
2
7
6
7
+
2
0
4
8
1
0
2
4
32767
x
+
2048
1024
102432767x+2048
So taking (0,-2) and (-3,-6) then it is -2-(-6)/0-(-3) or 4/3
Answer:324x^3-828x^2-63x+-9\20
Step-by-step explanation: