The quantity of sugar required for 2/4 of the recipe is 1/3 cups
<h3>How to solve fraction?</h3>
let
- x = quantity of sugar needed
Ratio of sugar to recipe
2/3 : 1 = x : 2/4
2/3 ÷ 1 = x ÷ 2/4
2/3 × 1/1 = x × 4/2
2/3 = x × 2
2/3 = 2x
x = 2/3 ÷ 2
x = 2/3 × 1/2
= 2/6
x = 1/3 cups
Therefore, the quantity of sugar required for 2/4 of the recipe is 1/3 cups
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-(11+sqrt(121-4*18))/2 = -(11 +sqrt(49))/2 = -9
Or
-(11-sqrt(121-4*18))/2 = -(11-sqrt(49))/2 = -2
D is the answer
n, n + 2, n + 4 - three consecutive even integers
the twice the sum of the second and third: 2[(n + 2) + (n + 4)]
twelve less than six times the first: 6n - 12
The equation:
2[(n + 2) + (n + 4)] = 6n - 12
2(n + 2 + n + 4) = 6n - 12
2(2n + 6) = 6n - 12 <em>use distributive property</em>
(2)(2n) + (2)(6) = 6n - 12
4n + 12 = 6n - 12 <em>subtract 12 from both sides</em>
4n = 6n - 24 <em>subtract 6n from both sides</em>
-2n = -24 <em>divide both sides by (-2)</em>
n = 12
n + 2 = 12 + 2 = 14
n + 4 = 12 + 4 = 16
<h3>Answer: 12, 14, 16</h3>
Answer:
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