as you already know, to get the inverse of any expression we start off by doing a quick switcheroo on the variables and then solving for "y", let's do so.
![\stackrel{h(x)}{y}~~ = ~~6\sqrt[3]{2x+5}-1\implies \stackrel{\textit{quick switcheroo}}{x~~ = ~~6\sqrt[3]{2y+5}-1} \\\\\\ x+1=6\sqrt[3]{2y+5}\implies \cfrac{x+1}{6}=\sqrt[3]{2y+5}\implies \left( \cfrac{x+1}{6} \right)^3=\left( \sqrt[3]{2y+5} \right)^3](https://tex.z-dn.net/?f=%5Cstackrel%7Bh%28x%29%7D%7By%7D~~%20%3D%20~~6%5Csqrt%5B3%5D%7B2x%2B5%7D-1%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bquick%20switcheroo%7D%7D%7Bx~~%20%3D%20~~6%5Csqrt%5B3%5D%7B2y%2B5%7D-1%7D%20%5C%5C%5C%5C%5C%5C%20x%2B1%3D6%5Csqrt%5B3%5D%7B2y%2B5%7D%5Cimplies%20%5Ccfrac%7Bx%2B1%7D%7B6%7D%3D%5Csqrt%5B3%5D%7B2y%2B5%7D%5Cimplies%20%5Cleft%28%20%5Ccfrac%7Bx%2B1%7D%7B6%7D%20%5Cright%29%5E3%3D%5Cleft%28%20%5Csqrt%5B3%5D%7B2y%2B5%7D%20%5Cright%29%5E3)
Answer:
you cant send pictures unless created on a graphing website but ill try to help. you first have to simplify y, and if you could comment a clearer equation that would be nice because your equation is confusing(cant tell if its all together
Answer:
68 degrees
Step-by-step explanation:
The ladder, the building and the ground together make up a right triangle with angle of elevation to be determined.
The side opposite this angle is 10 ft; the distance of the foot of the ladder from the building is 4 ft. Thus,
tan x = (opp side) / (adj side) = 10/4. Using the inverse tangent function, we find that the angle in question is
arctan (10/4) = 68 degrees
