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3 years ago

5. A ladder leans against a building. The top of the ladder touches the building 10 feet above the ground. The foot of the

Mathematics

1 answer:

jek_recluse [69]3 years ago

8 0

Answer:

68 degrees

Step-by-step explanation:

The ladder, the building and the ground together make up a right triangle with angle of elevation to be determined.

The side opposite this angle is 10 ft; the distance of the foot of the ladder from the building is 4 ft. Thus,

tan x = (opp side) / (adj side) = 10/4. Using the inverse tangent function, we find that the angle in question is

arctan (10/4) = 68 degrees

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Question

Alik [6]

Here, we are required to find the equation, in terms of w, that could be used to find the dimensions of the storage unit in feet.

The polynomial is;. 3w³ + 22w + 24w = 5440ft³.

From the question;

Let the width = w
length, l = 3w + 4
height, h = w + 6

The volume of a rectangular prism is given by the product of its length, width and height. Thus;

Volume = l × w × h

Therefore, Volume, V = (3w +4) × w × (w +6)

To obtain the required polynomial, we expand the expression for Volume above;

V = (3w² + 4w) × (w + 6)

V = (3w² + 4w) × (w + 6)V = 3w³ + 22w² + 24w.

However, the volume of the rectangular prism has been given to be 5440 cubic feet.

Therefore, the polynomial is;

3w³ + 22w + 24w = 5440ft³.

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2 years ago

Read 2 more answers

Who do you simplify 6/10

il63 [147K]

Answer:

the simplified form is 3/5

Step-by-step explanation:

5 0

3 years ago

Which of these numbers has the highest value? -22, 0.0099, 0, -1, (-1)

Oliga [24]

.0099 is the only positive number above zero and would have the highest value

5 0

3 years ago

Evaluate using Definite integrals

swat32

Since $[0,4]=[0,1]\cup(1,4]$ , we can rewrite the integral as

$\displaystyle \int_0^1f(t)\;dt + \int_1^4 f(t)\; dt$

Now there is no ambiguity about the definition of f(t), because in each integral we are integrating a single part of its piecewise definition:

$\displaystyle \int_0^1f(t)\;dt = \int_0^11-3t^2\;dt,\quad \int_1^4 f(t)\; dt = \int_1^4 2t\; dt$

Both integrals are quite immediate: you only need to use the power rule

$\displaystyle \int x^n\;dx=\dfrac{x^{n+1}}{n+1}$

to get

$\displaystyle \int_0^11-3t^2\;dt = \left[t-t^3\right]_0^1,\quad \int_1^4 2t\; dt = \left[t^2\right]_1^4$

Now we only need to evaluate the antiderivatives:

$\left[t-t^3\right]_0^1 = 1-1^3=0,\quad \left[t^2\right]_1^4 = 4^2-1^2=15$

So, the final answer is 15.

4 0

4 years ago

Please help! Will mark brainiest!!!!

brilliants [131]

Answer:

This is the alternate exterior angle theorem

Step-by-step explanation:

This is because angle 2 and angle 7 are in the outer part of each side of opposite lines

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3 years ago