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Firdavs [7]
3 years ago
11

I need help l don’t know what to do

Mathematics
1 answer:
dangina [55]3 years ago
7 0

Answer:

It would just the intersecting point: (-4, -1)

Step-by-step explanation:

You might be interested in
element x is a radioactive isotope such that every 32 years, its mass decreases by half. given that the initial mass of the samp
VashaNatasha [74]

Answer:

the answer is 31.9 years

Step-by-step explanation:

initial mass,  M_{0}  = 150 gram

half life, t_{half\hspace{0.1cm}life} = 32 years

new mass = half of initial mass = M = 0.5M_{0}

formula , M = M_{0} e^{\frac{\ln\frac{1}{2}}{t_{half} }\times x } where x is the number of years required.

therefore 0.5 M_{0}  = M_{0} e^{\frac{\ln\frac{1}{2}}{t_{half} }\times x } = M_{0} e^{-0.0217x}

therefore -0.0217 x = \ln{0.5} = -0.693  

therefore x = \frac{-0.693}{-0.0217} = 31.942

8 0
3 years ago
What is 1/2 times 14x
lesya [120]

Answer:

7x

Step-by-step explanation:

This quantity is the same as obtained when dividing 14x by 2:  7x

5 0
3 years ago
There are 4 pizzas and 3 people. How much would each person get if each person had the same amount?
julia-pushkina [17]
Each person would have 4/3 of a pizza, or C. 
6 0
3 years ago
Read 2 more answers
Consider functions of the form f(x)=a^x for various values of a. In particular, choose a sequence of values of a that converges
sleet_krkn [62]

Answer:

A. As "a"⇒e, the function f(x)=aˣ tends to be its derivative.

Step-by-step explanation:

A. To show the stretched relation between the fact that "a"⇒e and the derivatives of the function, let´s differentiate f(x) without a value for "a" (leaving it as a constant):

f(x)=a^{x}\\ f'(x)=a^xln(a)

The process will help us to understand what is happening, at first we rewrite the function:

f(x)=a^x\\ f(x)=e^{ln(a^x)}\\ f(x)=e^{xln(a)}\\

And then, we use the chain rule to differentiate:

f'(x)=e^{xln(a)}ln(a)\\ f'(x)=a^xln(a)

Notice the only difference between f(x) and its derivative is the new factor ln(a). But we know  that ln(e)=1, this tell us that as "a"⇒e, ln(a)⇒1 (because ln(x) is a continuous function in (0,∞) ) and as a consequence f'(x)⇒f(x).

In the graph that is attached it´s shown that the functions follows this inequality (the segmented lines are the derivatives):

if a<e<b, then aˣln(a) < aˣ < eˣ < bˣ < bˣln(b)  (and below we explain why this happen)

Considering that ln(a) is a growing function and ln(e)=1, we have:

if a<e<b, then ln(a)< 1 <ln(b)

if a<e, then aˣln(a)<aˣ

if e<b, then bˣ<bˣln(b)

And because eˣ is defined to be the same as its derivative, the cases above results in the following

if a<e<b, then aˣ < eˣ < bˣ (because this function is also a growing function as "a" and "b" gets closer to e)

if a<e, then aˣln(a)<aˣ<eˣ ( f'(x)<f(x) )

if e<b, then eˣ<bˣ<bˣln(b) ( f(x)<f'(x) )

but as "a"⇒e, the difference between f(x) and f'(x) begin to decrease until it gets zero (when a=e)

3 0
4 years ago
I need help with question 3!! Will give brainliest!!!
alex41 [277]

Answer:

x=4

Step-by-step explanation:

3(3x+2)=7(x+2)         Cross product

9x+6=7x+14              Solve for x

9x-7x=14-6

2x=8

x=8/2

x=4

6 0
3 years ago
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