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svlad2 [7]
3 years ago
10

element x is a radioactive isotope such that every 32 years, its mass decreases by half. given that the initial mass of the samp

le reached 150 grams, to the nearest tenth of a year?
Mathematics
1 answer:
VashaNatasha [74]3 years ago
8 0

Answer:

the answer is 31.9 years

Step-by-step explanation:

initial mass,  M_{0}  = 150 gram

half life, t_{half\hspace{0.1cm}life} = 32 years

new mass = half of initial mass = M = 0.5M_{0}

formula , M = M_{0} e^{\frac{\ln\frac{1}{2}}{t_{half} }\times x } where x is the number of years required.

therefore 0.5 M_{0}  = M_{0} e^{\frac{\ln\frac{1}{2}}{t_{half} }\times x } = M_{0} e^{-0.0217x}

therefore -0.0217 x = \ln{0.5} = -0.693  

therefore x = \frac{-0.693}{-0.0217} = 31.942

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A store spends 30% of its budget on maintenance. its yearly budget is $150,000.how much is spent on maintenance?
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It would be: 150,000*0.30 = 45000

so, your answer is $45,000

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Can someone help me solve the inequality-2x+4>8 with the steps? Thanks
stellarik [79]

\huge\text{Hey there!}

\rm{-2x + 4 > 8}

\large\textsf{SUBTRACT  4 to BOTH SIDES}

\rm{-2x + 4 - 4 > 8 - 4}

\large\textsf{CANCEL puts 4 - 4 because that gives you 0}

\large\textsf{KEEP: 8 - 4 because that helps solve for the x-value}

\rm{8 - 4 = \boxed{\bf 4}}

\rm{NEW\  EQUATION: -2x > 4}

\large\textsf{DIVIDE -2 to BOTH SIDES}

\mathsf{\dfrac{-2}{-2}>\dfrac{4}{-2}}

\mathsf{CANCEL\  out: \dfrac{-2}{-2}\  because\  that\  gives\  you\  1}

\mathsf{KEEP: \dfrac{4}{-2} \ because \ it \ helps \you \ compare\  to \  the \ x-value }

\mathsf{\dfrac{4}{-2} = \boxed{\bf -2}}

\rm{\bold{x < -2 }}

\rm{It\ is \ an\  O PENED \ circle \  shaded \  to \ the \ left \ side \ of \ the \ number  \ line}

\boxed{\boxed{\large\textsf{Answer: } \mathsf{\bf x < -2}}}\huge\checkmark

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8 0
3 years ago
(20 points and brainlest to whoever answers correctly!!!)
Stells [14]

Answer:

y = -2/3x - 11

Step-by-step explanation:

Steps to find the perpendicular bisector:

1) Find the midpoint of line PQ

Midpoint formula: (\frac{x_{1} + x_{2} }{2} \\, \frac{y_{1} + y_{2}}{2})

Midpoint of line PQ = (6, -2)

2) Find the slope of line PQ

Slope formula: \frac{y_{2} - y_{1}}{x_{2} - x_{1}}

Slope of line PQ = 3/2

3) Find the negative reciprocal of the slope of PQ

To find the negative reciprocal just swap the numerator and denominator and add a negative sign. If it is already negative it will become positive.

In this case it will be -2/3

4) Write the equation of line PQ in slop-intercept form.

Slope-intercept form: y = mx + b

This is what it will look like for line PQ: y = \frac{3}{2}x + b

5) Plug the points of the midpoint into the line and solve for the intercept (b)

This is what it will look like: -2 = \frac{3}{2}(6) + b

-2 = 18/2 + b

-2 = 9 + b

-11 = b

6) Write the equation of the perpendicular bisector

m = the negative reciprocal of the slope of PQ = -2/3

This is what the equation will look like: y = -2/3x - 11

Hope this helped! Please give Brainliest!

5 0
3 years ago
I need help ASAP PLS
mote1985 [20]

Answer:

write one what I don't get it

4 0
3 years ago
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