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3 years ago

PLZZZ HELP will mark brainliest!

Mathematics

1 answer:

erica [24]3 years ago

8 0

Answer:

(3,8): No, (-1,-11): Yes, (2,7): Yes, (0,-6): No

Step-by-step explanation:

Basically, you just substitute x and y with the numbers given.

18x - 3y = 15

y = 6x - 5

(3,8):

18(3) - 3(8) = 15

54 - 24 = 30 It is not equal to 15, so it does not work.

y = 6x - 5

8 = 6(3) - 5

8 = 13 It is not equal to 8, so it does not work.

Therefore, (3,8) is not a solution.

Try this for every pair and you will find that (-1,-11) and (2,7) are solutions.

I hope this helps!

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Is the point (-3, 2) a solution of x - 5y < 7? Explain how you know.

aivan3 [116]

Answer:

yes

Step-by-step explanation:

Substitute x = - 3 and y = 2 into the left side of the inequality and compare the value obtained with the right side.

- 3 - 5(2) = - 3 - 10 = - 13 < 7

Thus (- 3, 2) is a solution of the inequality

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3 years ago

What figure was made after connecting the points?

cupoosta [38]

It's not a figure its a letter!(I think) It's the letter 'R'.

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3 years ago

We would like to create a confidence interval.

Vlada [557]

Answer:

c.A 90% confidence level and a sample size of 300 subjects.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level $1-\alpha$ , we have the confidence interval with a margin of error of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

In this problem

The proportions are the same for all the options, so we are going to write our margins of error as functions of $\sqrt{\pi(1-\pi)}$

a.A 99% confidence level and a sample size of 50 subjects.

$n = 50$

99% confidence interval

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

The margin of error is

$M = z\sqrt{\frac{\pi(1-\pi)}{n}} = \frac{2.575}{\sqrt{50}}\sqrt{\pi(1-\pi)} = 0.3642\sqrt{\pi(1-\pi)}$

b.A 90% confidence level and a sample size of 50 subjects.

$n = 50$

90% confidence interval

So $\alpha = 0.1$ , z is the value of Z that has a pvalue of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

The margin of error is

$M = z\sqrt{\frac{\pi(1-\pi)}{n}} = \frac{1.645}{\sqrt{50}}\sqrt{\pi(1-\pi)} = 0.2623\sqrt{\pi(1-\pi)}$

c.A 90% confidence level and a sample size of 300 subjects.

$n = 300$

90% confidence interval

So $\alpha = 0.1$ , z is the value of Z that has a pvalue of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

The margin of error is

$M = z\sqrt{\frac{\pi(1-\pi)}{n}} = \frac{1.645}{\sqrt{300}}\sqrt{\pi(1-\pi)} = 0.0950\sqrt{\pi(1-\pi)}$

This produces smallest margin of error.

d.A 99% confidence level and a sample size of 300 subjects.

$n = 300$

99% confidence interval

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

The margin of error is

$M = z\sqrt{\frac{\pi(1-\pi)}{n}} = \frac{2.575}{\sqrt{300}}\sqrt{\pi(1-\pi)} = 0.1487\sqrt{\pi(1-\pi)}$

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3 years ago

PLEASE HELP ME IVE BEEN ASKING FOR AN HOUR PLEASE

hoa [83]

Answer:

c is equal to 4

Step-by-step explanation:

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Answer:

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3 years ago

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