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enot [183]
4 years ago
12

Mr. Thomas wrote these true statements. If a figure is a triangle, the sum of the figure's interior angles is 180. Figure ABC is

a triangle. Which conclusion can be drawn? Using the law of detachment, the sum of the interior angles of ABC is 180. Using the law of detachment, if the sum of a figure’s interior angles is 180, then the figure is a triangle. Using inductive reasoning, the sum of the interior angles of ABC is 180. Using inductive reasoning, if the sum of a figure’s interior angles is 180, then the figure is a triangle.
Mathematics
2 answers:
zhannawk [14.2K]4 years ago
3 0
Law of Detachment
If p then q. Given p is true. Conclude q is true.

In this problem, "if p then q" is "If a figure is a triangle, the sum of the figure's interior angles is 180."

Then you are told p is true. In this problem that is "<span>Figure ABC is a triangle."

You can now conclude that q is true.
In this problem, q is "</span><span>the sum of the interior angles of ABC is 180"

Answer: Option A.
</span>
Katen [24]4 years ago
3 0

Answer:

A.  Using the law of detachment, the sum of the interior angles of ABC is 180.

Step-by-step explanation:

Got it right on Edgenuity

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      ½ (the larger intercepted arc minus<span> the smaller intercepted arc)
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5 0
4 years ago
Solve the system <br> 2x+2y+z=-2 <br> -x-2y+2z=-5<br> 2x+4y+z=0
drek231 [11]

The values of (x,y,z) are (3,-1,-2) , if the given are equations 2x+2y+z=- 2,-x-2y+2z=-5 and 2x+4y+z=0.

Step-by-step explanation:

The given is,

                          2x+2y+z=- 2.......................................(1)

                         -x-2y+2z=-5......................................(2)

                            2x+4y+z=0.........................................(3)

Step:1

           Equation (2) is multiplied by -1            ( Eqn(2) × -1 )

                                         x+2y-2z=5.............................(4)

          Subtract the equation (1) and (4)

                                        2x+2y+z=- 2

                                         x+2y-2z=5

                 ( - )

           (2x-x)+(2y-2y)+(z+2z)=(-2-5)

                                                  x+3z=-7......................(5)

Step:2

          Equation (2) is multiplied by -2                 ( Eqn(2) × -2)

                                        2x+4y-4z=10........................(6)

         Subtract equation (6) and (3),                  

                                        2x+4y-4z=10

                                         2x+4y+z=0

                   ( - )

       (2x-2x)+(4y-4y)+(-4z-z)= (10-0)

                                                     -5z=10

                                                         z = - \frac{10}{5}

                                                         z = -2

         From the equation (5),

                                                  x+3z=-7  

                                          x+(3)(-2)=-7

                                                           x = -7+6

                                                            x = -1

         From equation (1),

                                            2x+2y+z=- 2

          Substitute x and z values,

                               (2)(-1)+2y+(-2)=-2

                                                     2y - 4=2

                                                           2y=4-2

                                                           2y=2

                                                            y=\frac{2}{2}

                                                             y = 1

Step:3

                Check for solution,

                                  -x-2y+2z=-5

                Substitute x,y and z values,

               -(-1)-(2)(1)+(2)(-2)=-5

                                         1-2-4=-5

                                                    -5 = -5

Result:

              The values of (x,y,z) are (3,-1,-2) , if the given are equations 2x+2y+z=- 2,-x-2y+2z=-5 and 2x+4y+z=0.

8 0
4 years ago
carl puts $1.10 in his piggy bank every day in the month of july. his total savings was $55.00 at the end of june. whats the bes
Dmitriy789 [7]
I'm assuming the first time you said "July" you meant June. If he continues his rate of 1.10 every day in the month of July he will have a total of 110.00. That would be 55+55.
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The answer would be $124.50:)
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