The difference between the gas prices in 2013 and 2001 is 3.00
<h3>The linear equation of the graph
</h3>
Start by calculating the slope of the line of best fit using:
From the line of best fit, we have:
![m = \frac{3 - 2}{8 - 4}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7B3%20-%202%7D%7B8%20-%204%7D)
The regression equation is then represented as:
So, we have:
![y = \frac 14(x -4) + 2](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%2014%28x%20-4%29%20%2B%202)
![y = \frac 14x -1 + 2](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%2014x%20-1%20%2B%202)
![y = \frac 14x +1](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%2014x%20%2B1)
Express as decimals
![y = 0.25x +1](https://tex.z-dn.net/?f=y%20%3D%200.25x%20%2B1)
<h3>The price of the gas</h3>
In 2001, the value of x is 1
So, we have:
In 2013, the value of x is 13.
So, we have:
So, the difference (d) between the prices is:
![d = 4.25 - 1.25](https://tex.z-dn.net/?f=d%20%3D%204.25%20-%201.25)
Hence, the difference between the gas prices in 2013 and 2001 is 3.00
Read more about linear regression at:
brainly.com/question/26137159