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vesna_86 [32]
3 years ago
13

a proton at the large hadron collider at CERN travels at 295,000,000 meters per second. How long does it take the proton to go a

round the 17 mile circumference of the collider?
Mathematics
2 answers:
Arisa [49]3 years ago
7 0

<u>Answer:</u>

9.27 x 10^-5 seconds

<u>Step-by-step explanation:</u>

We are given the speed of the proton at which it travels  i.e. 295,000,000 meters per second.

And we also know the total circumference of the collider = 17 mile.

So to find the time taken the proton to travel around the circumference of the collider, we first need to make the units same.

1 mile = 1609.34 meters

17 mile = 1609.34 * 17 = 27358.78

Time taken by the proton = distance / speed

=  27358.78 / 295000000

= 9.27 x 10^-5

Therefore, it takes 9.27 x 10^-5 or 0.0000927 seconds for the proton to go around 17 mile circumference of the collider.

Nady [450]3 years ago
5 0

Answer: It takes 0.000092742 seconds the proton to go arond the 17 mile circumference of the collider.

Solution:

Velocity: v=295,000,000 meters / second

Time: t=?

Distance: d=17 miles (1609.344 meters / 1 mile)→d=27,358.848 meters

v=d/t

Replacing the given values:

295,000,000 meters / second = 27,358.848 meters / t

Solving for t:

(295,000,000 meters / second) t = 27,358.848 meters

t=(27,358.848 meters) / (295,000,000 meters / second)

t=0.000092742 seconds

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