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vesna_86 [32]
3 years ago
13

a proton at the large hadron collider at CERN travels at 295,000,000 meters per second. How long does it take the proton to go a

round the 17 mile circumference of the collider?
Mathematics
2 answers:
Arisa [49]3 years ago
7 0

<u>Answer:</u>

9.27 x 10^-5 seconds

<u>Step-by-step explanation:</u>

We are given the speed of the proton at which it travels  i.e. 295,000,000 meters per second.

And we also know the total circumference of the collider = 17 mile.

So to find the time taken the proton to travel around the circumference of the collider, we first need to make the units same.

1 mile = 1609.34 meters

17 mile = 1609.34 * 17 = 27358.78

Time taken by the proton = distance / speed

=  27358.78 / 295000000

= 9.27 x 10^-5

Therefore, it takes 9.27 x 10^-5 or 0.0000927 seconds for the proton to go around 17 mile circumference of the collider.

Nady [450]3 years ago
5 0

Answer: It takes 0.000092742 seconds the proton to go arond the 17 mile circumference of the collider.

Solution:

Velocity: v=295,000,000 meters / second

Time: t=?

Distance: d=17 miles (1609.344 meters / 1 mile)→d=27,358.848 meters

v=d/t

Replacing the given values:

295,000,000 meters / second = 27,358.848 meters / t

Solving for t:

(295,000,000 meters / second) t = 27,358.848 meters

t=(27,358.848 meters) / (295,000,000 meters / second)

t=0.000092742 seconds

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If you shift the linear parent function, f(x) = x, down 6 units, what is the equation of the new function?
Colt1911 [192]

Answer:

f(x)=x-6

Step-by-step explanation:

Given : Parent function : f(x)=x

To Find : If you shift the linear parent function, f(x) = x, down 6 units, what is the equation of the new function?

Solution:

Parent function : f(x)=x

Shift the given function down by 6 units.

Rule : The graph f(x) shifts down by b units

So, f(x)→f(x)-b

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6 0
3 years ago
3y=11-2x, 3x=y-11 linear equation solve using the algebraic method check solution
tamaranim1 [39]

Answer:

(x, y) = (- 2, 5)

Step-by-step explanation:

given the 2 equations

3y = 11 - 2x → (1)

3x = y - 11 → (2)

Rearrange (2) expressing y in terms of x

add 11 to both sides

y = 3x + 11 → (3)

Substitute y = 3x + 11 into (1)

3(3x + 11) = 11 - 2x

9x + 33 = 11 - 2x ( add 2x to both sides )

11x + 33 = 11 ( subtract 33 from both sides )

11x = - 22 ( divide both sides by 11 )

x = - 2

Substitute x = - 2 in (3) for corresponding value of y

y = (3 × - 2) + 11 = - 6 + 11 = 5

As a check

substitute x = - 2, y = 5 into (1) and (2) and if the left side equals the right side then these values are the solution.

(1) :  left side = (3 × 5) = 15

right side = 11 - (2 × - 2) = 11 + 4 = 15 ⇒ left = right

(2) : left side = (3 × - 2 ) = - 6

right side = 5 - 11 = - 6 ⇒ left = right

solution = (- 2, 5 )



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Which of the following is grater than 0.30 and less than 0.50?
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None of the numbers on the list of choices that you posted
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