Given : tan 235 = 2 tan 20 + tan 215
To Find : prove that
Solution:
tan 235 = 2 tan 20 + tan 215
Tan x = Tan (180 + x)
tan 235 = tan ( 180 + 55) = tan55
tan 215 = tan (180 + 35) = tan 35
=> tan 55 = 2tan 20 + tan 35
55 = 20 + 35
=> 20 = 55 - 35
taking Tan both sides
=> Tan 20 = Tan ( 55 - 35)
=> Tan 20 = (Tan55 - Tan35) /(1 + Tan55 . Tan35)
Tan35 = Cot55 = 1/tan55 => Tan55 . Tan35 =1
=> Tan 20 = (Tan 55 - Tan 35) /(1 + 1)
=> Tan 20 = (Tan 55 - Tan 35) /2
=> 2 Tan 20 = Tan 55 - Tan 35
=> 2 Tan 20 + Tan 35 = Tan 55
=> tan 55 = 2tan 20 + tan 35
=> tan 235 = 2tan 20 + tan 215
QED
Hence Proved
Smaller!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
500 bricks.
Step-by-step explanation:
There are 250 bricks used to build a wall that is 20 feet high how many bricks will be used to build a wall is 40 feet high?
To solve e the above question, we have:
20 feet high = 250 bricks
40 feet high = x bricks
Cross Multiply
20 feet × x bricks = 40 feet × 250 bricks
x bricks = 40 feet × 250 bricks/20 feet
x bricks = 500 bricks
Therefore, 500 bricks will be used to build a wall is 40 feet high.
2. The mean is the average so it phase shifted up five points where as the range is the difference between the highest and lowest # which wouldn't change if all the numbers were adjusted.
