The area of a rhombus is the product of the diagonals divided by 2. In this question, the diagonals are given, so that's really easy. Let's convert the measures to meters, that'll help for the final area calculation:
Area of one rhombus: (0.52x0.30)/2 = 0.078 m²
In 60 m², you can fit 60/0.078 tiles. That's 769.23, rounded to 770 since you'll have to cut up the last tile.
<u>Given</u>:
Four coordinates lying on the 3rd quadrant of the Cartesian plane are as follows: 
- C' = (–6, –5)
- D' = (–6, –3)
- E' = (–4, –3)
- F' = (–4, –5)
<u>Translation</u>:
Since you've been asked to translate the coordinates of the vertices 2 units right and 8 units up, you'll need to add 2 to its x-coordinate and 8 to its y-coordinate.
C'(–6, –5)
ㅤㅤ= C'(–6 + 2, –5 + 8)
ㅤㅤ= C'(–4, 3)
D'(–6, –3)
ㅤㅤ= D'(–6 + 2, –3 + 8)
ㅤㅤ= D'(–4, 5)
E'(–4, –3)
ㅤㅤ= E'(–4 + 2, –3 + 8)
ㅤㅤ= E'(–2, 5)
F'(–4, –5)
ㅤㅤ= F'(–4 + 2, –5 + 8)
ㅤㅤ= F'(–2, 3)
<u>Final </u><u>answer</u>:
- C' = (–4, 3)
- D' = (–4, 5)
- E' = (–2, 5)
- F' = (–2, 3)
The area of the whole figure is 92.1
the area of the rectangle is 78
the area of the half circle is 14.13
add them together, you get 92.1
hope this helps :D
The time taken by the object to fall from 15 m on the Mercury which has a gravity of 3.7 m/s² is 10.54 seconds.
<h3>What is kinematics?</h3>
It is the study of the motion of a body without considering mass. And the reason behind them is neglected.
The object is on Mercury and starts falling from rest.
As it is on Mercury there is no air resistance to account for.
Gravity on Mercury is 3.7 m/s².
Then the time taken by the object to fall from 15 m will be given as

More about the kinematics link is given below.
brainly.com/question/25638908
#SPJ1
Answer:
the answer is d
Step-by-step explanation:
radius is 14
height is 12
formula is 2(pi)(r)(h)+2(pi)(r)^2
multiply it all together and you get d