Answer:
a) a = 7.37, b = 15.13, C = 67°
b) 1 triangle
Step-by-step explanation:
<h3>a)</h3>
Two angles and one side are given. That means the triangle is uniquely determined, and the remaining sides can be found from the Law of Sines.
The third angle is ...
C = 180° -A -B = 180° -29° -84° = 67°
Then the Law of Sines tells you ...
a/sin(A) = b/sin(B) = c/sin(C)
a = sin(A)/sin(C)·c = sin(29°)/sin(67°)·14 ≈ 7.37
b = sin(B)/sin(C)·c = sin(84°)/sin(67°)·14 ≈ 15.13
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<h3>b)</h3>
Ordinarily, when the given angle (B = 30°) is opposite the shorter of the given sides (b = 10 < a = 20), it means there are two possible solutions to the triangle.
However, when the sine of the angle is exactly equal to the ratio of the given sides: sin(30°) = 10/20 = 1/2, the larger angle can only be 90°. That is, the one triangle that can be formed is a right triangle.
The Law of Sines tells you this.
sin(A)/a = sin(B)/b
sin(A) = (a/b)sin(B) . . . . . . multiply by 'a'
A = arcsin(a/b·sin(B)) = arcsin(20/10·sin(π/6)) = arcsin(1)
A = 90°
Answer: 2b = 3g
Step-by-step explanation:
This is quite basic to solve, below is a Step by step explanation:
from the given question we have that;
- A fire hydrant with a blue cap provides water at a rate of 1,500 gallons per minute.
i.e b = 1500 gallons per minute
- A fire hydrant with a green cap provides water at a rate of 1,000 gallons per minute.
g = 1000 gallons per minute.
Our questions tells us to write the equation which relates the flow of water from the blue hydrant, b, to the flow from the green hydrant, g.
ANS:
Since flow from blue hydrant b = 1500 gallons per minute, we have that
b = 3 * 500
b = 3 * 1000/2 g
b = 3/2 g
equation gives 2b = 2g
cheers i hope this helped !!
Answer:
Rounding
Step-by-step explanation:
You can look this word up to verify
Midpoint of JN is at coordinates (3,2)
Step-by-step explanation:
Coordinates of j= (10,-2)
Coordinates of N = (-4,6)
We need to find midpoint of JN.
The formula used to find midpoint is:

We are given:

Putting values and finding midpoint of JN




So, midpoint of JN is at coordinates (3,2)
Keywords: Midpoint of line
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