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Softa [21]
2 years ago
10

Explain why 0.32 is greater than 0.102

Mathematics
2 answers:
lyudmila [28]2 years ago
7 0

Answer:0.32 is closer the the number one then 0.102 is

Step-by-step explanation:

artcher [175]2 years ago
6 0

Answer:

0.32 is greater than 0.102

Step-by-step explanation:

Because the more numbers behind the decimal the lower it is

EX. 0.1 is greater than 0.472648726464364872648264

You might be interested in
Which equation represents a parabola that opens upward has a minimum at x=3 and has a line of symmetry at x=3
umka2103 [35]

Answer:

y=x^2-6x+5

Step-by-step explanation:

Let us consider the equation y=x^2-6x+5

For a quadratic equation in a standard form, y=ax^2+bx+c, the axis of symmetry is the vertical line x = \frac{-b}{2a}.

Here in this case we have, a=1, b=-6 , c =5

Putting the values we get,

x = \frac{-(-6)}{2\times 1} = \frac{6}{2} =3

We can see that the axis of symmetry is x=3 and the graph is giving minimum at x=3.

Therefore, the required equation is y=x^2-6x+5. Refer the image attached.


4 0
3 years ago
Read 2 more answers
What is 1,376 x 6 equal to
Arte-miy333 [17]

Answer:

8256

Step-by-step explanation:

3 0
2 years ago
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The actual distance between the two houses is 44.1ft. The contractor measures the distance as 46ft. Find the relative error of t
mixer [17]
The correct answer is: 44.1ft - 46ft = -1.9ft/44.1ft = .043% relative error. Please mark Brainliest if helpful
6 0
2 years ago
Which is the slope of the line that passes through the points (3,5) and (8, 7)?
Rainbow [258]

The answer would be 2/5 because you have to put in a slope equation which gives you your answer.

3 0
3 years ago
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Question 2 of 5
AlekseyPX

Given:

The different recursive formulae.

To find:

The explicit formulae for the given recursive formulae.

Solution:

The recursive formula of an arithmetic sequence is f(n)=f(n-1)+d, f(1)=a,n\geq 2 and the explicit formula is f(n)=a+(n-1)d, where a is the first term and d is the common difference.

The recursive formula of a geometric sequence is f(n)=rf(n-1), f(1)=a,n\geq 2 and the explicit formula is f(n)=ar^{n-1}, where a is the first term and r is the common ratio.

The first recursive formula is:

f(1)=5

f(n)=f(n-1)+5 for n\geq 2.

It is the recursive formula of an arithmetic sequence with first term 5 and common difference 5. So, the explicit formula for this recursive formula is:

f(n)=5+(n-1)(5)

f(n)=5+5(n-1)

Therefore, the correct option is A, i.e., f(n)=5+5(n-1).

The second recursive formula is:

f(1)=5

f(n)=3f(n-1) for n\geq 2.

It is the recursive formula of a geometric sequence with first term 5 and common ratio 3. So, the explicit formula for this recursive formula is:

f(n)=5(3)^{n-1}

Therefore, the correct option is F, i.e., f(n)=5(3)^{n-1}.

The third recursive formula is:

f(1)=5

f(n)=f(n-1)+3 for n\geq 2.

It is the recursive formula of an arithmetic sequence with first term 5 and common difference 3. So, the explicit formula for this recursive formula is:

f(n)=5+(n-1)(3)

f(n)=5+3(n-1)

Therefore, the correct option is D, i.e., f(n)=5+3(n-1).

6 0
3 years ago
Read 2 more answers
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