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sukhopar [10]
2 years ago
15

Simplify the following expression. 11 to the 6th power 114 to the 4th power

Mathematics
1 answer:
vichka [17]2 years ago
6 0

Answer:

11^6 = 1,771,561

114^4 = 1.68 x 10^8 or 1.68896e8

Step-by-step explanation:

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Y=-2x+4 the first blank will be your slope and the second blank will be where your line crosses the y intercept
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He fills the pencil holder with sand before he wraps it to make it feel like a heavy, expensive gift. How much sand will he need
torisob [31]

Answer:

Answer choice d

Step-by-step explanation:

To find the volume of this triangular prism, you first need to find the area of the triangular base. The formula for the area of a triangle is bh/2, which in this case is 3*2/2=3 square units. Multiplying this by the height of the prism, 3.5, you get a total of 10.5 cubic inches, or answer choice d. Hope this helps!

5 0
2 years ago
A running circuit is in the shape of a triangle with lengths of 6km, 6.5km and 7km. What are the sizes of the angles (in minutes
Rudik [331]

A <u>triangle</u> is an example of a class of <em>figures</em> referred to as <em>plane shapes</em>. It has <u>three</u> straight <u>sides</u> and <u>three</u> internal <u>angles</u> which sum up to 180^{o}. The <em>measures</em> of the internal <u>angles</u> of the <u>triangle</u> given in the question are A = 52.6^{o}, B = 59.4^{o}, and C = 68^{o}.

A <u>triangle</u> is an example of a class of <em>figures</em> referred to as <em>plane shapes</em>. It has <u>three</u> straight <u>sides</u> and <u>three</u> internal <u>angles</u> which sum up to 180^{o}.

Considering the given question, let the <u>sides</u> of the triangle be: a = 6 km, b = 6.5 km, and c = 7 km.

Apply the <em>Cosine rule</em> to have:

c^{2} = a^{2} + b^{2} - 2ab Cos C

So that;

7^{2} = 6^{2} + (6.5)^{2} - 2(6 * 6.5) Cos C

49 = 36 + 42.25 - 78Cos C

78 Cos C = 78.25 - 49

               = 29.25

Cos C = \frac{29.25}{78}

         = 0.375

C = Cos^{-1} 0.375

   = 67.9757

C = 68^{o}

Apply the <em>Sine rule</em> to determine the <u>value</u> of B,

\frac{b}{Sin B} = \frac{c}{Sin C}

\frac{6.5}{Sin B} = \frac{7}{Sin 68}

SIn B = \frac{6.5 *Sin 68}{7}

         = 0.861

B = Sin^{-1} 0.861

   = 59.43

B = 59.4^{o}

Thus to determine the value of A, we have;

A + B + C = 180^{o}

A + 59.4^{o} + 68^{o} = 180^{o}

A = 180^{o} - 127.4

  = 52.6

A = 52.6^{o}

Therefore the <u>sizes</u> of the <em>internal angles</em> of the triangle are: A = 52.6^{o}, B = 59.4^{o}, and C = 68^{o}.

For more clarifications on applications of the Sine and Cosine rules, visit: brainly.com/question/14660814

#SPJ1

8 0
1 year ago
Rewrite the equation by completing the square.<br> x^2+ 12x + 36 = 0
svetoff [14.1K]

Answer:

(x+6)^2 =0

Step-by-step explanation:

x^2+ 12x + 36 = 0

Subtract 36 from each side

x^2+ 12x + 36-36 = 0-36

x^2 +12x = -36

Take the coefficient of x

12

Divide by 2

12/2 =6

Square it

6^2 =36

Add this to each side

x^2+ 12x + 36 = -36+36

(x+12/2)^2 = 0

(x+6)^2 =0

4 0
3 years ago
Read 2 more answers
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