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3 years ago

Quadrilateral ABCD has the following vertices:

Mathematics

2 answers:

GenaCL600 [577]3 years ago

6 0

9514 1404 393

Answer:

yes

Step-by-step explanation:

The figure can be shown to be a parallelogram by showing the sum of endpoints of the diagonals is the same.

A +C = B +D

(0, 6) +(0, -4) = (0, 2) = (3, 5) +(-3, -3) . . . . diagonals bisect each other

If the diagonals of a quadrilateral bisect each other, it is a parallelogram. A parallelogram with a right angle is a rectangle. So, ABCD is a rectangle.

_____

<em>Additional comment</em>

The midpoint of each diagonal is half the sum of the end point coordinates. That is, the midpoints are (0, 2)/2 = (0, 1). Since calculation of the midpoints requires both sums be divided by 2, we can tell the midpoints are the same if the sums are the same.

ohaa [14]3 years ago

6 0

Answer:

Yes, because opposite sides are parallel, and \angle A∠Aangle, A is a right angle.

Step-by-step explanation:

khan academy

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(PLEASE HELP ASAP)

UNO [17]

9514 1404 393

Answer:

A. 3×3

B. [0, 1, 5]

C. (rows, columns) = (# equations, # variables) for matrix A; vector x remains unchanged; vector b has a row for each equation.

Step-by-step explanation:

A. The matrix A has a row for each equation and a column for each variable. The entries in each column of a given row are the coefficients of the corresponding variable in the equation the row represents. If the variable is missing, its coefficient is zero.

This system of equations has 3 equations in 3 variables, so matrix A has dimensions ...

A dimensions = (rows, columns) = (# equations, # variables) = (3, 3)

Matrix A is 3×3.

B. The second row of A represents the second equation:

$0x_1+1x_2+5x_3=-1$

The coefficients of the variables are 0, 1, 5. These are the entries in row 2 of matrix A.

C. As stated in part A, the size of matrix A will match the number of equations and variables in the system. If the number of variables remains the same, the number of rows of A (and b) will reflect the number of equations. (The number of columns of A (and rows of x) will reflect the number of variables.)

6 0

3 years ago

F(x+1)+f(x+2)=2x+3; f(x)=?

Rama09 [41]

Answer:

$F=\frac{-xf+f+2x}{x+1};\quad \:x\ne \:-1$

Step-by-step explanation:

$1. \mathrm{Subtract\:}f\left(x+2\right)\mathrm{\:from\:both\:sides}\\
F\left(x+1\right)+f\left(x+2\right)-f\left(x+2\right)=2x+3f-f\left(x+2\right)

$

$2. \mathrm{Simplify}\\
F\left(x+1\right)=-xf+f+2x\\
$

$3. \mathrm{Divide\:both\:sides\:by\:}x+1;\quad \:x\ne \:-1\\
\frac{F\left(x+1\right)}{x+1}=-\frac{xf}{x+1}+\frac{f}{x+1}+\frac{2x}{x+1};\quad \:x\ne \:-1$

$4. \mathrm{Simplify}\\
F=\frac{-xf+f+2x}{x+1};\quad \:x\ne \:-1$

Final Answer: $F=\frac{-xf+f+2x}{x+1};\quad \:x\ne \:-1$

4 0

3 years ago

Select Equal or Not Equal to correctly classify each statement.

UkoKoshka [18]

1. Equal
2. Not Equal

5 0

3 years ago

Read 2 more answers

What's 1 and 2/3 times 1 and 1/3?

kari74 [83]

<span>1 and 2/3 time 1 and 1/3 is 2.22222222222 which rounds to 2.</span>

6 0

3 years ago

Read 2 more answers

Find the x-intercept of the parabola of with vertex (1,20) and the y-intercept (0,16). write your answer in this form: (x1,y1),(

svetoff [14.1K]

I assume that the parabola in this particular problem is one whose axis of symmetry is parallel to the y axis. The formula we're going to use in this case is (x-h)2=4p(y-k). We know variables h and k from the vertex (1,20) but p is not given. However, we can solve for p by substituting values x and y in the formula with the y-intercept:

(0-1)^2=4p(16-20)

Solving for p, p=-1/16.

Going back to the formula, we can finally solve for the x-intercepts. Simply fill in variables p, h and k then set y to zero:

(x-1)^2=4(-1/16)(0-20)
(x-1)^2=5
x-1=(+-)sqrt(5)
x=(+-)sqrt(5)+1

Here, we have two values of x

x=sqrt(5)+1 and
x=-sqrt(5)+1

thus, the answers are: (sqrt(5)+1,0) and (-sqrt(5)+1,0).

5 0

3 years ago