3x+4y=12
4y=12-3x
y=(12-3x)/4 <---------- This is f(x)
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3x+4y=12
3x=12-4y
x=(12-4y)/3
Therefore:
f⁻¹(x)=(12-4x)/3
=[4(3-x)]/3
Answer:
6
Step-by-step explanation:
Given : g(x) = and h(x)=2x-8.
g*h(x) =(2x-8).
We have square root(x-6) in composite function f*h(x).
So, we need to find the domain, we need to check for that values of x's, square root(x-4\6) would be defined.
Square roots are undefined for negative values.
Therefore, we can setup an inequality for it's domain x-6≥0.
Adding 4 on both sides, we get
x-6+6≥0+6.
x≥6.
