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VladimirAG [237]
3 years ago
15

How can you tell when an equation in one variable has infinitely many solutions or no solution?

Mathematics
1 answer:
Masteriza [31]3 years ago
6 0

Answer:

A system has infinitely many solutions when it is consistent and the number of variables is more than the number of nonzero rows in the rref of the matrix. For example if the rref is ��has solution set (4-3z, 5+2z, z) where z can be any real number.

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Yo tenía $ 2.00. Mi mamá me dio $ 10.00. Mi papá me dio $ 30.00. Mi tía y mi tío me dieron $ 100.00. Yo tenía otros $ 5.00. Cuán
Mkey [24]

Answer:

$147

Step-by-step explanation:

$2.00+$10.00+$30.00+$100.00+$5.00

=<u>$147</u>

7 0
3 years ago
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Find the volume of the solid generated by revolving the region enclosed by the triangle with vertices left parenthesis 2 comma 0
puteri [66]

The triangle is a right triangle with sides aligned with the x- and y-axes. The desired volume can be found several ways. Perhaps the easiest is to make use of the fact that the volume is the product of the area of the triangle and the length of the path of revolution of the centroid of the triangle.


The centroid of a triangle is located at the intersection point of the medians, one-third of the distance from any side toward the opposite vertex. Here, we want the radius to the centroid from the y-axis, so the side of interest is the one parallel to the y-axis.


In the x-direction, the altitude of the triangle is 6-2=4, so the centroid is located at 4/3 units from the left side, which is x=2. The x-coordinate of the centroid is then 2+4/3 = 10/3, and this is the radius of revolution for the area of the triangle.


The sides of the right triangle are of length 5 and 4, so the area is

... area = (1/2)bh = (1/2)·5·4 = 10 . . . . . square units


Then the volume of interest is

... V = 2π·(radius of revolution)·(area)

... V = 2π·(10/3)·10

... V = 200π/3 ≈ 209.44 . . . units³

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3 years ago
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prohojiy [21]

Answer:

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7 0
3 years ago
Is ten a perfect square
Contact [7]
Answer:
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7 0
3 years ago
Z-​4/​4+​8= z + 9, z - 3, z - 7, z + 7
Sladkaya [172]

The values of the expressions are -17/3, -29/3 and 13/3

<h3>How to solve the expressions?</h3>

The equation is given as:

z-​4/​4+​8= z + 9

Rewrite properly as

\frac{z-4}{4}+8= z + 9

Subtract 8 from both sides

\frac{z-4}{4}= z + 1

Multiply through by 4

z - 4 = 4z + 4

Evaluate the like terms

3z = -8

Divide by 3

z = -8/3

Substitute z = -8/3 in z - 3, z - 7 and z + 7

z - 3 = -8/3 - 3 = -17/3

z - 7 =  -8/3 - 7 = -29/3

z + 7 =  -8/3 + 7 = 13/3

Hence, the values of the expressions are -17/3, -29/3 and 13/3

Read more about expressions at:

brainly.com/question/723406

#SPJ1

7 0
2 years ago
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