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IrinaK [193]
3 years ago
10

What percent of values is between the first and third quartiles? its question 4

Mathematics
1 answer:
Naddika [18.5K]3 years ago
5 0

Answer:

answer

Step-by-step explanation:

5%

.......................

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A test is used to assess readiness for college. In a recent​ year, the mean test score was 21.2 and the standard deviation was4.
myrzilka [38]

Scores that are greater than 31 are significantly high.

Scores that are less than 11.4 are significantly low.

The test scores between 11.4 and 31 are not significantly low or significantly high.

<h3>How to Identify significance values?</h3>

We are given;

Standard deviation; s = 4.9

From the complete question, we are told to consider a value to be significantly low if its z score less than or equal to -2 or consider a value to be significantly high if its z score is greater than or equal to 2.

Thus;

2s = 2 * 4.9 = 9.8

Scores that are greater than 21.2 + 9.8 = 31 are significantly high.

Scores that are less than 21.2 - 9.8 = 11.4 are significantly low.

Thus, the test scores between 11.4 and 31 are not significantly low or significantly high.

Read more about significance values at; brainly.com/question/4621112

#SPJ1

6 0
2 years ago
Write a linear function f with the values f(0)=-1 and f(2)=-5​
Darya [45]

Answer:

f(x) = - 2x - 1

Step-by-step explanation:

Let the linear function f(x) is given by f(x) = ax + b where a and b are unknown constants.

Given that f(0) = -1 and f(2) = -5

Hence, a(0) + b = - 1, ⇒ b = - 1

Again from the condition given

a(2) + b = -5, ⇒ 2a - 1 = - 5, ⇒ 2a = - 4, ⇒ a = - 2.

Therefore, the linear function is f(x) = - 2x - 1 (Answer)

5 0
3 years ago
Enter the coefficients of the fifth Taylor polynomial T5(x) for the function f(x) = x5−3x4+2x2+5x−2 based at b=1. T5(x)= + (x−1)
DENIUS [597]

Compute the necessary values/derivatives of f(x) at x=1:

f(1)=3

f'(1)=2

f''(1)=-12

f'''(1)=-12

f^{(4)}(1)=48

f^{(5)}(1)=120

Taylor's theorem then says we can "approximate" (in quotes because the Taylor polynomial for a polynomial is another, exact polynomial) f(x) at x=1 by

T_5(x)=\dfrac3{0!}+\dfrac2{1!}(x-1)-\dfrac{12}{2!}(x-1)^2-\dfrac{12}{3!}(x-1)^3+\dfrac{48}{4!}(x-1)^4+\dfrac{120}{5!}(x-1)^5

T_5(x)=3+2(x-1)-6(x-1)^2-2(x-1)^3+2(x-1)^4+(x-1)^5

###

Another way of doing this would be to solve for the coefficients a,b,c,d,e,g in

f(x)=a+b(x-1)+c(x-1)^2+d(x-1)^3+e(x-1)^4+g(x-1)^5

by expanding the right hand side and matching up terms with the same power of x.

5 0
3 years ago
Help pls! Idk what to do with this one.
muminat

i have answers but im not sure if there correct but ill write them down anyway a.6 b.2,3,6,9 c.first of all its spelled dice not die and yes because it all equals 100:)

7 0
3 years ago
Simplify 2(2x-y)-4(x-y)+3y<br><br>please give the answer if you know how to solve it​
MakcuM [25]

Answer:

2( 2x - y ) -4( x - y ) +3y

4x - 2y - 4x + 4y + 3y

-2y + 4y + 3y

-2y +7y

5y

6 0
3 years ago
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