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AVprozaik [17]
2 years ago
10

What is the price per pound of watermelon? A. $0.25 B. $0.75 C. $1.40 D. $7.50

Mathematics
2 answers:
natali 33 [55]2 years ago
8 0

Answer:

B. 0.75

Step-by-step explanation:

this is what I think cuz the graph at 1 is 0.75

Salsk061 [2.6K]2 years ago
6 0
The answer is A $.025
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An after school job pays $46.50 for 6 hours of work. What is the unit rate?
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The unit rate is $7.75 because 46.50 divide by 6 is $7.75
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76. Currently, your savings for each month is capped at $400. If you start investing all of this into a savings plan earning 1%
Alexxandr [17]

Answer:

10 years and 10 months.

Step-by-step explanation:

The annually interest rate (ia) can be converted by monthly (im) by the equation:

(1 + im)¹² = 1 + ia

(1 + im)¹² = 1 +0.01

(1 + im)¹² = 1.001 (putting ln in both sides)

ln(1 + im)¹² = ln1.001

12*ln(1 + im) = 1.0x10⁻³

ln(1 + im) = 8.33x10⁻⁵(applying "e in both sides)

e^{ln(1 + im)} = e^{8.33x10^{-5}}

1 + im = 1.00083

im = 0.00083 = 0.083%

For a investimenting, the final amount (A) can be calculated by:

A = R*(\frac{(1+i)^n-1}{i} )

Where R is the amount invested per month, i is the interest, and n the number of months:

160000 = 400 *\frac{(1 +0.00083)^n - 1}{0.00083}

\frac{(1 +0.00083)^n - 1}{0.00083} = 400

1.00083ⁿ - 1 = 0.332

1.00083ⁿ = 1.332 (applying ln in both sides)

n*ln1.00083 = ln1.332

8.3x10⁻⁴n = 0.2867

n = 345.4 months

345.4 months *1 yea12 months = 10 years and 10 months.

7 0
3 years ago
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denis23 [38]
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6 0
2 years ago
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Ronald is 26 years old and starting an IRA (individual retirement account). He is going to invest $200 at the beginning of each
Licemer1 [7]

The formula for the future value A, given annual interest rate r, number of years t, and deposit amount P can be written as

... A = P(1 +r/12)((1+r/12)^(12t) -1)/(r/12)

Filling in the given numbers, you have

... A = 200(1+.0275/12)((1+.0275/12)^(12·39) -1)/(.0275/12) ≈ 167,868.30

The appropriate choice is $167,868.30.

_____

The formula is the one for the sum of a geometric series. It can be useful to consider the last deposit made as the first term of the series.

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