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hammer [34]
3 years ago
10

General solution for cos(5x)-cos(2x)=0

Mathematics
1 answer:
Irina-Kira [14]3 years ago
7 0
<span>Simplifying cos(5x) + cos(2x) = 0
 (5x) cos * 5x + cos(2x) = 0 
</span> 5cos * x + cos(2x) = 0 Multiply cos * x 5cosx + cos(2x) = 0
(2x) 5cosx + cos * 2x = 0
 5cosx + 2cos * x = 0 Multiply cos * x 5cosx + 2cosx = 0  5cosx + 2cosx = 7cosx 7cosx = 0 Solving 7cosx = 0 Solving for variable 'c'. cosx = 0 Simplifying cosx = 0

Hope this helps!

In short your answer is 0


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Free_Kalibri [48]

Answer:

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in the figure below trianglePQM and triangleQRP are right triangles. the measure of lineQM is 6 and the measure of lineQP is 8.
Kipish [7]

Answer:

Option 4 is correct. The length of PR is 6.4 units.

Step-by-step explanation:

From the given figure it is noticed that the triangle PQR and triangle MQR.

Let the length of PR be x.

Pythagoras formula

hypotenuse^2=base^2+perpendicular^2

Use pythagoras formula for triangle PQM.

PM^2=QM^2+PQ^2

PM^2=(6)^2+(8)^2

PM^2=36+64

PM^2=100

PM=10

The value of PM is 10. The length of PR is x, so the length of MR is (10-x).

Use pythagoras formula for triangle PQR.

PQ^2=QR^2+PR^2

(8)^2=QR^2+x^2

64-x^2=QR^2                   .....(1)

Use pythagoras formula for triangle MQR.

MQ^2=QR^2+MR^2

(6)^2=QR^2+(10-x)^2

36=QR^2+x^2-20x+100

36-x^2+20x-100=QR^2        .... (2)

From equation (1) and (2) we get

36-x^2+20x-100=64-x^2

20x-64=64

20x=128

x=6.4

Therefore length of PR is 6.4 units and option 4 is correct.

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Answer:

Step-by-step explanation:

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