Question

The equation 3x² - 4x + 6 = 0 has the roots α and β . Find the new equation with the roots (α/β²) and (β/α²) .

Answer 1

Answer:

${ \tt{sum = \alpha + \beta = \frac{4}{3} }} \\ { \tt{product = \alpha \beta = \frac{6}{3} = 2}} \\ \\ new \: roots : \\ { \bf{sum = \frac{ \alpha }{ { \beta }^{2} } + \frac{ \beta }{ { \alpha }^{2} } }} \\ \\ { \bf{ = \frac{ { \beta }^{2} \alpha + { \alpha }^{2} \beta }{ { (\alpha \beta )}^{2} } }} \\ \\ = { \bf{ \frac{ \alpha \beta ( \alpha + \beta )}{ {( \alpha \beta )}^{2} } }} \\ \\ = { \tt{ \frac{2( \frac{4}{3}) }{2 {}^{2} } }} \\ \\ sum = \frac{2}{3} \\ \\ { \bf{product = \frac{1}{ \alpha \beta }}} \\ = \frac{1}{2} \\ \\ { \boxed{ \tt{equation : {2x}^{2} + \frac{4}{3} x + 1 }}}$