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wolverine [178]
3 years ago
6

What is the slope of the line whose equation is 2y = 31 +4

Mathematics
1 answer:
satela [25.4K]3 years ago
7 0

Answer:

The slope of the line is zero and the y is 17.5

Step-by-step explanation:

2y=31+4

31+4= 35

2y=35

and then you divide and you get 17.5

The intercept is (0,\frac{35}{2}) and/or (0,17.5)

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Nookie1986 [14]
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3 0
3 years ago
S is directly proportional to the fifth power of t
Colt1911 [192]

Answer:

Im assuming this would simplify to

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7 0
3 years ago
An English professor assigns letter grades on a test according to the following scheme. A: Top 9% of scores B: Scores below the
sergeinik [125]

Answer:

The minimum score required for an A grade is 83.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 72.3 and a standard deviation of 8.

This means that \mu = 72.3, \sigma = 8

Find the minimum score required for an A grade.

This is the 100 - 9 = 91th percentile, which is X when Z has a pvalue of 0.91, so X when Z = 1.34.

Z = \frac{X - \mu}{\sigma}

1.34 = \frac{X - 72.3}{8}

X - 72.3 = 1.34*8

X = 83

The minimum score required for an A grade is 83.

5 0
3 years ago
Qual é 33⅓% de 108?​
makkiz [27]
0.333 x 108 = 35.96
= 36 (esta é a resposta final, eu não sei se você realmente precisa dela)
7 0
3 years ago
The missing exponent of the y-term must be ____? PLEASE HELP
a_sh-v [17]

Answer:

what is y term??

Step-by-step explanation:

hope it helps

7 0
3 years ago
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