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ser-zykov [4K]
3 years ago
12

The prodect of y and 4

Mathematics
1 answer:
Llana [10]3 years ago
4 0

Answer:

Step-by-step explanation:

The product of y and 4 is 4y

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5(m+3+n).................
snow_tiger [21]
What u want man whats de question
5 0
3 years ago
Read 2 more answers
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Delvig [45]

Answer:

y=\frac{1}{2}x+3

Step-by-step explanation:

Let the equation of the line be: y=mx+b

where m is the slope and b is the y-intercept.

The given straight line has a y-intercept at b=3

The equation is of the form y=mx+3

The line passes through the point (2,4).

Let us substitute x=2, and y=4 to find the value of m.

4=m(2)+3

4=2m+3\\4-3=2m\\1=2m\\m=\frac{1}{2}

The slope is m=\frac{1}{2}

Hence the equation of the line is  y=\frac{1}{2}x+3

4 0
3 years ago
WRITE EACH NUMBER tWo different ways
12345 [234]
1) 500+60+3 and 563
2) 1 hundreds + 0 tens + 9 ones and 100+0+9

3) 9 hundreds + 2 tens + 23 ones and 23 ones?? not possible!.

4) 370 and 300 + 70 + 0

Hope my answer helps!
6 0
3 years ago
Prove the theorem which states that the angle subtended by a cord is twice at the centre than at the circumference
Novay_Z [31]

9514 1404 393

Explanation:

<u>Given</u>:

  • The attached figure showing circle O, chord BC, central angle BOC and inscribed angle BAC
  • angle BAC = α + β

<u>Prove</u>:

  • angle BOC = 2×angle BAC

<u>Proof</u>:

∠BOA +∠BOC +∠AOC = 360° . . . . . sum of arcs of a circle is 360°

2α +∠BOA = 180°, 2β +∠AOC = 180° . . . . . sum of triangle angles is 180°

∠BOA = 180° -2α, ∠AOC = 180° -2β . . . . solve statement 2 for central angles

(180° -2α) +∠BOC +(180° -2β) = 360° . . . . . substitute into statement 1

∠BOC = 2(α +β) . . . . . add 2α+2β-360° to both sides

∠BOC = 2×∠BAC . . . . . substitute given for α+β; the desired conclusion

7 0
3 years ago
Is the relation a function? Why or why not?
tatuchka [14]

Answer: it is c

Step-by-step explanation:

It has two of the same domain

7 0
2 years ago
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