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3 years ago

Find the first three terms of the series represented by the formula 3(- 2)(n - 1).

Mathematics

1 answer:

enyata [817]3 years ago

8 0

Answer:

0, - 6, - 12

Step-by-step explanation:

To find the first 3 terms, substitute n = 1, 2, 3 into the formula

a₁ = 3(- 2)(1 - 1) = 3 × - 2 × 0 = 0

a₂ = 3(- 2)(2 - 1) = 3 × - 2 × 1 = - 6

a₃ = 3(- 2)(3 - 1) = 3 × - 2 × 2 = - 12

First 3 terms are 0, - 6, - 12

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Bailey brought a twin pack of gum for $2, this is 50 cents less than 2/3 the

Deffense [45]

Answer:

$3.75

Step-by-step explanation:

2/3 = $2.50

2.50/2 = 1.25

1.25x3 = 3.75

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3 years ago

The digits 4 comma 5 comma 6 comma 7 comma and 8 are randomly arranged to form a three-digit number. (Digits are not repeate

fenix001 [56]

Answer:

0.1 or 1/10

Step-by-step explanation:

The digits 4, 5, 6, 7 and 8 are randomly arranged to form a three digit number, where the digits are not repeated.

This is question of permutation.

Imagine this sum as; there are 3 boxes(blank spaces for digits) and 5 different fruits(digits) are to be put in these boxes, where a box can hold a maximum of only 1 fruit. The number of such permutations are: ⁵P₃

By formula (a! is factorial a):

ᵃPₙ $= \frac{a!}{(a-n)!}$

⁵P₃ $= \frac{5!}{(5-3)!}$

⁵P₃ $= \frac{5!}{2!}$

⁵P₃ $= \frac{5*4*3*2*1}{2*1}$

⁵P₃= 60

This is the total count of possible numbers that can be formed.

Now, for a number to be greater than 800 and even; first digit should necessarily be 8. Last digit can be 4 or 6. Using these conditions, there are 6 possibilities. 854, 864, 874, 846, 856, 876 are the numbers.

The probability that number is even and greater than 800 is:

$P=\frac{ favorable outcomes}{equally likely possible outcomes}$

$P=\frac{6}{60}$

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3 0

3 years ago

Plz help me and explain how you got the answer

Reptile [31]

So first (3 1/2) equals to 3+1/2 which is 7/2, same for(2 1/3), 2+1/3=7/3. It's asking for speed in laps per minute, so like how many labs did she swim per minute, which is labs over time——(7/2)/(7/3)=(7/2)*(3/7)=3/2. So she swam 3/2 labs per minute.

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3 years ago

the product of two consecutive integers is 5402. Build a function that can be used to solve for the integers. whatthose two inte

nasty-shy [4]

Using algebra...
n and n+2 are the integers
n*(n+2)=288
n^2+2n=288
n^2+2n-288=0
288=2*2*2*2*2*3*3=(2*2*2*2)*(2*3*3)=16*18 and 18-16=2
factor
(n+18)(n-16)=0
n+18=0
n=-18
n+2=-16
this is one solution
n-16=0
n=16
n+2=18

this is another solution
as you can see, it's just a matter of factoring
288

using arithmetic...
√288=16.97≈17

16 and 18 are the integers (as well as -16 and -18)

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3 years ago

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viktelen [127]

The answer is 1920. glad to assist you

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3 years ago

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