X1=4+x2=2 can someone tell me how do i do this?

Please help me with this word problem!!!

Inessa [10]

Answer:

The number of customers needed to break even is

$\simeq 6775.$

Step-by-step explanation:

Rent per month = $ 7200

Rent per year, $ $7200 \times 12$

= $ 86400 -------------(1)

Insurance per year = $ 4200 ---------(2)

Total direct cost for 2 servers (withoout tax) per year,

= $ $2 \times 15 \times 8 \times 5 \times 50$

= $ 60000

Total cost for helper ( without tax) per year,

= $ $4 \times 15 \times 5 \times \50$

= $ 15000

Total cost for employees per year (without tax),

= $ (60000 +15000) = $ 75000

Total cost per year for employees including tax,

$ $\frac {(75000 \times (100 + 6.2 + 1.45)}{100}$

= $ $\frac {(75000 \times 107.65 }{100}$

= $ 80737.5 -----------------------(3)

So,

total cost for running the restaurant (except food)

= (1) + (2) + (3) = $ $(86400 + 4200 + 80737.5)$

= $ 171337.5

Average total profit per customer,

= ( Average per customer payment - average cost of food per customer)

= $ (45.47 - 20.18)

= $ 25.29

So, total number of customer needed to break even,

= $\frac {171337.5}{25.29}$

\simeq 6775

7 0

2 years ago

Rosa saved $100 to spend on vacation. For the first 3 days of her vacation she spent $20 each day then for the next 2 days, afte

Wewaii [24]

Answer:

hope this helps you

6 0

2 years ago

4^2 x 2<br> Please will give brainliests

vitfil [10]

4^2 = 16
16 x 2 = 32
32, Hope this helps!

4 0

3 years ago

Read 2 more answers

Confirm that quadrilateral ABCD is a parallelogram. Measure and record the slope of each of its sides.

VMariaS [17]

Answer:

AB = 1.5

BC = 0

CD = 1.5

AD = 0

Step-by-step explanation:

Sample Answer for Plato

5 0

3 years ago

Read 2 more answers

According to the University of Nevada Center for Logistics Management, 6% of all mer-

Fudgin [204]

Answer:

a) The point estimate of the proportion of items returned for the population of

sales transactions at the Houston store = 12/80 = 0.15

b) The 95% confidence interval for the proportion of returns at the Houston store = [0.0718 < p < 0.2282].

c) Yes.

We set an hypothesis and construct a test statistics. The test statistics result gives us:

Z calculated = 2.2545, and this gives us the p-value = 0.0121. We assumed 95% confident interval. Hence, the level of significance (α) = 5%. Conclusively, since the p-value ==> 0.0121 is less than (α) = 5%, the test is significant. Hence, the proportion of returns at the Houston store is significantly different from the returns for the nation as a whole.

Step-by-step explanation:

a) Point estimate of the proportion = number of returned items/ total items sold = 12/80 = 0.15.

b) By formula of confident interval:

CI(95%) = p ± Z* $\sqrt{\frac{p*(1-p)}{n} } = 0.15 \pm 1.96 *\sqrt{\frac{0.15*(1-0.15)}{80} }$ ,

CI(95%) = [0.0718 < p < 0.2282]

c) The hypothesis:

$H_{0}$ : The proportion of returns at the Houston store is not significantly different from the returns for the nation as a whole.

$H_{a}$ : The proportion of returns at the Houston store is significantly different from the returns for the nation as a whole.

The test statistics:

Z = $\frac{\hat{p} - p_{0}}{\sqrt{\frac{p*(1-p)}{n} }}$ , where $p_{0}$ is the proportion of nation returns.

Z calculated = 2.2545, and this gives us the p-value = 0.0121. We assumed 95% confident interval. Hence, the level of significance (α) = 5%. Conclusively, since the p-value ==> 0.0121 is less than (α) = 5%, the test is significant. Hence, the proportion of returns at the Houston store is significantly different from the returns for the nation as a whole.

6 0

3 years ago