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Drupady [299]
3 years ago
6

If x = 3 solves the system shown below, what must be the value of a?

Mathematics
2 answers:
gogolik [260]3 years ago
8 0

Answer:

-4

Step-by-step explanation:

y=7

y=ax3+19

Fiesta28 [93]3 years ago
3 0

Answer:

pls

Step-by-step explanation:

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3 years ago
A math test is worth 100 points and has 38 problems. Each problem is worth either 5 points or 2 points. How many problems of eac
Nat2105 [25]

Answer:

<em><u>5</u></em><em><u> </u></em><em><u>points</u></em><em><u> </u></em><em><u>question</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>8</u></em>

<em><u>and</u></em><em><u> </u></em><em><u>2</u></em><em><u> </u></em><em><u>po</u></em><em><u>ints</u></em><em><u> questions</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>3</u></em><em><u>0</u></em><em><u> </u></em><em><u>!</u></em><em><u>!</u></em>

Step-by-step explanation:

Let the number of 5 points questions be x and number of the 2 points questions be y !!

Given :- The paper has 38 problems

i.e,

number of 5 points Q + number of 2point Q = 38

=> x + y = 38

=> x = 38 - y .... ( i )

And , The test worth 100 pts :-

There must be x number of Questions which carry 5 points and there must y number of questions which carries 2 points ( as assume above )

so, 5x + 2y = 100 .... ( ii )

Putting value of the x in ( ii )

5 ( 38 - y ) + 2y = 100

190 - 5y + 2y = 100

- 3y = - 90

y = 30

Putting value of y in ( i )

x = 38 - y

x = 38 - 30

x = 8

So, the Number of 5points Question is

x = 8

and , the number of 2 points questions is y = 30 !!

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4 years ago
Best answer for why do you want to work at a library
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4 0
3 years ago
The formula s = StartRoot StartFraction S A Over 6 EndFraction EndRoot gives the length of the side, s, of a cube with a surface
never [62]

Answer:

2\sqrt{2}\ ft\ longer

Step-by-step explanation:

<u>Area Of A Cube </u>

Suppose a cube with side length s, the area of one side is

A_s=s^2

Since the cube has 6 sides, the total area is

A=6A_s=6s^2

But if we have the area, we can solve the above formula for s to get

A=6s^2

\displaystyle s=\sqrt{\frac{A}{6}}

We have two different cubes with areas 1,200 square inches and  768 square inches. Let's compute their side lengths

\displaystyle s_1=\sqrt{\frac{1,200}{6}}=\sqrt{200}

\displaystyle s_1=10\sqrt{2}\ ft

\displaystyle s_2=\sqrt{\frac{768}{6}}=\sqrt{128}

\displaystyle s_2=8\sqrt{2} ft

The difference between them is

10\sqrt{2}\ ft-8\sqrt{2}\ ft=2\sqrt{2}\ ft\approx 2.83\ ft

The side of the cube with area 1,200 square inches is 2\sqrt{2}\ ft longer then the side of the cube with area 768 square inches

7 0
4 years ago
Read 2 more answers
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