Answer:
12
Step-by-step explanation:
3 + x>-9 x=12 15>-9
Answer:
See explanation
Step-by-step explanation:
In ΔABC, m∠B = m∠C.
BH is angle B bisector, then by definition of angle bisector
∠CBH ≅ ∠HBK
m∠CBH = m∠HBK = 1/2m∠B
CK is angle C bisector, then by definition of angle bisector
∠BCK ≅ ∠KCH
m∠BCK = m∠KCH = 1/2m∠C
Since m∠B = m∠C, then
m∠CBH = m∠HBK = 1/2m∠B = 1/2m∠C = m∠BCK = m∠KCH (*)
Consider triangles CBH and BCK. In these triangles,
- ∠CBH ≅ ∠BCK (from equality (*));
- ∠HCB ≅ ∠KBC, because m∠B = m∠C;
- BC ≅CB by reflexive property.
So, triangles CBH and BCK are congruent by ASA postulate.
Congruent triangles have congruent corresponding sides, hence
BH ≅ CK.
Answer: x = 40.81 or 41
Step-by-step explanation:
A = B = 21
C = 35
Hypotenuse = x
Calculating Hypotenuse:
21^2 + 35^2 = x^2
=> 441 + 1225 = x^2
=> x^2 = 1666
=> x = 40.81 or 41
Answer:
Adult required in the case of “a” 28 and in the case of “b” the adult requirement is 19.
Step-by-step explanation:
(a) The percentage of adult that support the change is 20 percent.
Now calculate the number of adult required.
Given p = 0.20
Use the below condition:

Since 35 adults are already there so required adults are 63 -35 = 28
(b) The percentage of adult that support the change is 25 percent.
Now calculate the number of adult required.
Given p = 0.25
Use the below condition:

Since 35 adults are already there so required adults are 54 -35 = 19
.

Converting to spherical coordinates, we have

On the other hand, we can parameterize the boundary of

by

with

and

. Now, consider the surface element



So we have the surface integral - which the divergence theorem says the above triple integral is equal to -


as required.