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1 answer:

3 0

So first you would divide 1950/6 to find the amount for one year of their age.
Then you would multiply that by the ages, which should get you 4 numbers, then you all those numbers together. Try 9750.

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Your store Brown stock in 1 gallon batch is one serving of rice grains require 1.5 cups of brown stock how many servings of gree

sladkih [1.3K]

The number of servings of greens that can be made with one batch of route stock is 0.67 batches.

<h3>Conversion of gallons to cups</h3>

In order to determine the answer, the first step is to convert gallons to cups

1 gallon = 16 cups

<h3>Number of servings of greens that can be made</h3>

The second step is to divide 16 cups by 1.5 cups.

16 / 1.5 = 10.67 batches

To learn more about division, please check: brainly.com/question/194007

3 0

2 years ago

Select all of the following expressions that are equivalent to 16a+40 .

lina2011 [118]

The first one is true
<span>4(4a+10) is
</span>16 a + 40 after distribution

The second one is also true
<span>2(8a+20)
16a + 40 after distribution

Third is not true
</span><span>4a(4+10a)
</span><span>16a + 40a^2 after distribution

Last one is also true
</span><span>8(2a+5)
16a + 40 after distribution

Hope this helps :)</span>

5 0

3 years ago

The vertex of the parabola below is at the point (1,-3). Which of the equations

kramer

Answer:

Step-by-step explanation:

A. X=-3(4-1)

3 0

3 years ago

Read 2 more answers

Use the discriminant to determine the number of solutions to the quadratic equation 3x^2+5x=-1

kari74 [83]

Answer:

Two real distinct solutions

Step-by-step explanation:

Hi there!

<u>Background of the Discriminant</u>

The discriminant $b^2-4ac$ applies to quadratic equations when they are organised in standard form: $ax^2+bx+c=0$ .

All quadratic equations can be solved with the quadratic formula: $x = \frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}}$ .

When $b^2-4ac$ is positive, it is possible to take its square root and end up with two real, distinct values of x.

When it is zero, we won't be taking the square root at all and we will end up with two real solutions that are equal, or just one solution.

When it is negative, it is impossible to take the square root and we will end up with two non-real solutions.

<u>Solving the Problem</u>

We're given the above equation. It hasn't been organised completely in $ax^2+bx+c=0$ , but we can change that by adding 1 to both sides to make the right side equal to 0:

$3x^2+5x+1=0$ <u />