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kompoz [17]
2 years ago
11

What is |-26|? (a) -26, (b) 26, (c) 0, (d) 1

Mathematics
1 answer:
S_A_V [24]2 years ago
4 0

Answer:

(b)26

Step-by-step explanation:

Step 1: Isolate the absolute value expression.

Step2: Set the quantity inside the absolute value notation equal to + and - the quantity on the other side of the equation.

Step 3: Solve for the unknown in both equations.

Step 4: Check your answer analytically or graphically.

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Write an inequality for the following, more than 2,500 people can attend the convention
sergeinik [125]

Answer:

a

Step-by-step explanation:

8 0
3 years ago
P(X< ) 1-P(X> ) A softball pitcher has a 0.626 probability of throwing a strike for each curve ball pitch. If the softball
Mashutka [201]

Answer:

19.49% probability that no more than 16 of them are strikes

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 30, p = 0.626

So

\mu = E(X) = np = 30*0.626 = 18.78

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{30*0.626*0.374} = 2.65

What is the probability that no more than 16 of them are strikes?

Using continuity correction, this is P(X \leq 16 + 0.5) = P(X \leq 16.5), which is the pvalue of Z when X = 16.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{16.5 - 18.78}{2.65}

Z = -0.86

Z = -0.86 has a pvalue of 0.1949

19.49% probability that no more than 16 of them are strikes

7 0
2 years ago
Please help will mark brainliest
beks73 [17]

Answer:

m\angle N=57^{\circ}

Step-by-step explanation:

From the isosceles-base theorem, the measure of the angles adjacent to the pair of congruent sides of the triangle are equal. Since the problem declares LM\cong LN, the remaining unknown angles are equal (m\angle N=m\angle M). The sum of the interior angles of a triangle always add up to 180^{\circ}$.

Therefore:

m\angle N\cdot 2+66=180,\\m\angle N\cdot 2=114,\\m\angle N=\fbox{$57^{\circ}$} .

7 0
2 years ago
Read 2 more answers
The look out point of a lighthouse is 30 feet above sea level. A boat is 20 feet away from the base of the lighthouse. What is t
olya-2409 [2.1K]
Call the angles of depression D.

then tan(D)=20/30, or I

arctan(tan(D)) = arctan(⅔)

D=33.690. A is the answer

your calculator probably uses tan^-1 rather than arctan
8 0
3 years ago
Read 2 more answers
Please help soon! Will give branliest!
rosijanka [135]

Answer:

1. .26

2. .29

3. .22

4. .23

Step-by-step explanation:

3.1 ÷ 12 = .26

2.92 ÷ 10 = .29

3.52 ÷ 16 = .22

1.85 ÷ 8 = .23

<em>good luck, i hope this helps :)</em>

3 0
2 years ago
Read 2 more answers
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