6x+3y=33..........(1)
4x+y=15
y=15-4x.........(2)
substitute value of y from (2) in (1)
6x+3(15-4x)=33
distribute 3 over the bracket
6x+45-12x =33
-6x=33-45
-6x=-12
x=2
plugging this value of x in equation 2 we get
15-4x=y
15-4(2)=y
y=15-8
y=7
Answer is x=2 and y=7
The discounted price is $14.40. Hope this helped.
Answer:
Step-by-step explanation:
183.5
<h3>The dimensions of the gym floor could be 150 feet by 120 feet</h3><h3>The dimensions of the gym floor could be 225 feet by 180 feet</h3>
<em><u>Solution:</u></em>
Given that,
The dimensions of the swimming pool and the gym are proportional
The pool is 75 feet long by 60 feet wide
To find: set of possible dimensions for the gym
To determine the possible dimensions for the gym, you would use the same number to multiply both 75 and 60
<em><u>One set of dimensions are:</u></em>
75 x 2 = 150
60 x 2 = 120
The dimensions of the gym floor could be 150 feet by 120 feet
<em><u>Other set of dimensions:</u></em>
75 x 3 = 225
60 x 3 = 180
The dimensions of the gym floor could be 225 feet by 180 feet
