Answer:
y - 7 = 4(x - 35)
Step-by-step explanation:
The fundamental theorem of calculus states that:
= f(x).
So using the fundamental theorem of calculus, you can find that h'(x) = f(x).
The question tells you that f(x) is periodic with a period of 8, so f(x) repeats itself every 8 units.
Using this, you can find that the slope of h(x) at x = 35 is the same as the slope of h(x) at x = 3, which is 4.
The slope of h(x) at x = 35 is 4.
Now I have to find the value of h(x) when x = 35. It is the area under f(x) from 0 to 35.
The area underneath f(x) from 0 to 35 is 7. When x = 35, h(x) = 7.
Now use the point-slope formula to write the equation of the tangent line.
The answer is <u>y - 7 = 4(x - 35)</u>
6 is 75% of 8. 6/8 can be simplified to 3/4, which is easier to see as 75%.
Answer:
Step-by-step explanation:
Answer:
Surface area is found:
Surface Area = 1700 cm²
Step-by-step explanation:
(The cereal box is shown in the ATTACHMENT)
The surface area of a rectangular prism can be found by added the areas of all 6 sides of the rectangular prism.
L = length = 20 cm
H = height = 30 cm
W = Width = 5 cm
<h3 /><h3>Side 1:</h3>
A(1) = L×H
A(1) = 20×30
A(1) = 600 cm²
<h3>Side 2:</h3>
As the measurements of the side at the back of side 1 has the same measurement of side 1. then:
A(2) = 600 cm²
<h3>Side 3:</h3>
A(3) = L×W
A(3) = 20×5
A(3) = 100 cm²
<h3>Side 4:</h3>
As the measurements of the side at the back of side 4 has the same measurement of side 4. then:
A(4) = 100 cm²
<h3>Side 5:</h3>
A(5) = H×W
A(5) = 30×5
A(5) = 150 cm²
<h3>Side 6:</h3>
As the measurements of the side at the back of side 5 has the same measurement of side 5. then:
A(6) = 150 cm²
<h3>Surface Area:</h3>
Adding areas of all the sides
A(1) + A(2) + A(3) +A(4) + A(5) + A(6) = 600 + 600 + 100 +100 + 150 +150
Surface Area = 1700 cm²
9514 1404 393
Answer:
x = 1 or 5
Step-by-step explanation:
The notion of "cross-multiplying" is the idea that the numerator on the left is multiplied by the denominator on the right, and the numerator on the right is multiplied by the denominator on the left. This looks like ...

Then the solution proceeds by eliminating parentheses, and solving the resulting quadratic equation.

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<em>Comment on "cross multiply"</em>
Like a lot of instructions in Algebra courses, the idea of "cross multiply" describes <em>what the result looks like</em>. It doesn't adequately describe how you get there. The <em>one and only rule</em> in solving Algebra problems is "<em>whatever is done to one side of the equation must also be done to the other side of the equation</em>." If you multiply one side by one thing and the other side by a different thing, you are violating this rule.
What looks like "cross multiply" is really "<em>multiply by the product of the denominators</em> and cancel like terms from numerator and denominator." Here's what that looks like with the intermediate steps added.
