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PSYCHO15rus [73]
3 years ago
7

Please help 99 points No wrong answer please.

Mathematics
2 answers:
forsale [732]3 years ago
6 0
The total value of the triangle should be 180 degrees.
So 53 + 60 is 113...
so x = 180-113
the value of x is 67
iogann1982 [59]3 years ago
6 0
Hey there,

Your correct answer would be in the attachment below.

Hope this helps buddy.

~Jurgen

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2,10,18,26 find the 61st term
saw5 [17]

Answer:

482

Step-by-step explanation:

We can see that the numbers shown resemble an arithmetic sequence because they have a common difference. The formula for the nth term of an arithmetic sequence is:

a_{n} =a_{1} +(n-1)d

Where a_{1} is the first term, a_{n} is the nth term, and d is the common difference. To find the 61st term, all we need is the first term and the common difference. By looking at what given, we can say the first term is 2. Now, to find the common difference, we find the difference of a term from the term before it. In this case we can do 10-2, which is 8 , or the common difference. Since we have everything we need, it can be plugged into the equation:

a_{61} =2 + (61 - 1)*8\\a_{61} = 2 + 60*8\\a_{61} = 2 + 480\\a_{61} = 482

So, the 61st term is 482.

4 0
2 years ago
35POINTS PLZ HELP FAST
meriva

Answer:

Step-by-step explanation:

16.76FT^3

3 0
2 years ago
Which value is the solution to the equation -8 = 6 - 7x? <br>A. -7 <br>B. - 2 <br>C. 2 <br>D. 5​
r-ruslan [8.4K]

Step-by-step explanation:

the answer is c: 2..............

8 0
3 years ago
8/9k + 9/5 = -4 - 9/7k
Mamont248 [21]

Answer:

k=-1827/685

Step-by-step explanation:

8/9k+9/5=-4-9/7k

8/9k-(-9/7k)=-4-9/5

8/9k+9/7k=-20/5-9/5

56/63k+81/63k=-29/5

137/63k=-29/5

k=(-29/5)/(137/63)

k=(-29/5)(63/137)

k=-1827/685

7 0
3 years ago
Which of the following correctly expresses sin (70) + sin(30) as a product?
JulsSmile [24]

Answer:

2sin50 cos20

Step-by-step explanation:

We need to write sin (70) + sin(30) as a product. The formula used here is :

\sin A+\sin B=2\sin (\dfrac{A+B}{2})\cos(\dfrac{a-b}{2})

Here, A = 70 and B = 30

So,

\sin 70+\sin 30=2\sin (\dfrac{70+30}{2})\cos(\dfrac{70-30}{2})\\\\\sin 70+\sin 30=2\sin 50\cos20

So, the value of sin (70) + sin(30) is 2sin50 cos20. Hence, the correct option is  (c).

7 0
3 years ago
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