Answer:
.2625
Step-by-step explanation:
logb(3) = 0.5646, logb(4) = 0.7124, and logb(5) = 0.8271
logb(5/3)
We know that logx ( y/z) = logx (y) - logz (z)
logb ( 5) - logb(3)
0.8271 - 0.5646
.2625
The height of the object after 1 sec is 284 feet
<h3>Equation of height of an object</h3>
Given the equation of height of an object expressed as:
h(t) = -16t^2 + 300t
We are to find the height of the object after 1 sec. To do that, we will substitute t = 1 into the following expression
h(t) = -16t^2 + 300t
h(1) = -16(1)^2 + 300(1)
h(1) = -16 + 300
h(1) = 284ft
Hence the height of the object after 1 sec is 284 feet
Learn more on maximum height here: brainly.com/question/12446886
20=10%
times 10
200=100%
he earned $200 at the parlor
