The admission price is $6 and the rides are $2 each.
The equation of the perpendicular bisector of BC with B(-2, 1), and C(4, 2) is y = 7.6 - 6•x
<h3>Which method can be used to find the equation of the perpendicular bisector?</h3>
The slope, <em>m</em>, of the line BC is calculated as follows;
- m = (2 - 1)/(4 - (-2)) = 1/6
The slope of the perpendicular line to BC is -1/(1/6) = -6
The midpoint of the line BC is found as follows;

The perpendicular bisector is the perpendicular line constructed from the midpoint of BC.
The equation of the perpendicular bisector in point and slope form is therefore;
(y - 1.5) = -6•(x - 1)
y - 1.6 = -6•x + 6
y = -6•x + 6 + 1.6 = 7.6 - 6•x
Which gives;
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The y-intercept which is the point at which x = 0 is; A: -10
<h3>How to find the y-intercept?</h3>
The general form of an equation of a line in slope intercept form is;
y = mx + c
where;
m is slope
c is y-intercept
We are given the slope;
m = -4
Now, the line passes through the point 0, -10. Thus;
(y - y1)/(x - x1) = -4
(y + 10)/(x - 0) = -4
y + 10 = -4x
y = -4x - 10
Thus, the y-intercept which is the point at which x = 0 is; y = -10
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2y + 2(y-2) = 5y - 3(y-10)
2y + 2y - 4 = 5y -3y +30
4y - 4 = 2y + 30
4y - 2y = 30 + 4
2y = 34
y = 34/2
y = 17