Answer:
happy birthday
Step-by-step explanation:
thank you
Answer:
Step-by-step explanation:
C
l
2
+
2
K
B
r
→
2
K
C
l
+
B
r
2
Given:
300
g
of
C
l
2
300
g
of
K
B
r
(a) Mass of
C
l
2
= 300g
Molecular mass of
C
l
2
= 2(35.45) = 70.906 g
/
m
o
l
No.of moles of
C
l
2
=
m
a
s
s
/
m
o
l
a
r
m
a
s
s
=
300
/
70.906
=
4.23
moles
Mass of
K
B
r
=
300
g
Molar mass of
K
B
r
=
39
+
79.9
=
118.9
g
/
m
o
l
No.of moles of
K
B
r
=
300
/
118.9
=
2.52
moles
Now,
Consider the equation:
C
l
2
+
2
K
B
r
→
2
K
C
l
+
B
r
2
1
mole of
C
l
2
= 2 moles of
K
C
l
4.23
moles of
C
l
2
= 2x4.23=
8.46
moles
2
moles of
K
B
r
= 2 moles of
K
C
l
2.52
moles of
K
B
r
=
2.52
moles
Now convert moles to mass,
Mass of
K
C
l
produced by
C
l
2
=
8.46
×
70.906
=
599.8
g
Mass of
K
C
l
produced by potassium bromide =
2.52
×
74.5
=
187.74
g
Answer:a
Step-by-step explanation:
throughout the table it is presented that the answer, A, is correct becuase within the percentages is is obvious that a is correct.
Answer:
Divide one of the sides in the bigger triangle by its corresponding side in the smaller triangle to determine the scale factor for the smaller triangle to the bigger triangle.
Answer:
So, the first three nonzero terms in the Maclaurin series are:
Step-by-step explanation:
From exercise we have the next function y = 6 sec(3x).
We know that Maclaurin series for the function sec x, have the following form:
So, for the given function y = 6 sec(3x), we get:
So, the first three nonzero terms in the Maclaurin series are:
