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uranmaximum [27]
3 years ago
5

heather writes the equations below to represent two lines drawn on the coordinate plane. –6x 18y = 0 4x – 12y = 20 after applyin

g the linear combination method, heather arrived at the equation 0 = 60. what conclusion can be drawn about the system of equations? the equation has no solution; therefore, the system of equations has no solution. the equation has a solution at (0, 60); therefore, the system of equations has a solution at (0, 60). the equation has infinite solutions; therefore, the system of equation as infinite solutions. the equation has a solution at (0, 0); therefore, the system of equations has a solution at (0, 0).
Mathematics
2 answers:
Tju [1.3M]3 years ago
7 0

The <em><u>correct answer</u></em> is:

The equation has no solution; therefore, the system of equations has no solution.

Explanation:

When solving a system of equations, after we combine the equations, if we find that there is no solution, that means that there is no solution to the entire system of equations.

Ierofanga [76]3 years ago
6 0
<span>In this example the equation has no solution. This is because, in algebra, the variables are what is solved for. Here, through the combination method, Heather has determined that 0 = 60, which is not true. Zero cannot equal a number other than itself; additionally there are no variables that were solved for in this equation. By this it is meant that "x" is not given a value and "y" is not given a value. These two values would be used for coordinates to plot the line on a graph</span>
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Need to write steps and solve <br> thanks
nalin [4]

<u>Answer:</u>

The coordinates of endpoint V is (7,-27)

<u>Solution:</u>

Given that the midpoint of line segment UV is (5,-11) And U is (3,5).

To find the coordinates of V.

The formula for mid-point of a line segment is as follows,

Midpoint of UV is \frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}

As per the formula,  \frac{x_{1}+x_{2}}{2}=5, \frac{y_{1}+y_{2}}{2}=-11

Here x_{1}=3; y_{1}=5

Substituting the value of x_{1} we get,

\frac{3+x_{2}}{2}=5

3+x_{2}=5\times2

x_{2}=10-3

x_{2}=7

Substituting the value of x_{2} we get,

\frac{5+y_{2}}{2}=-11

5+y_{2}=-11\times2

y_{2}=-22-5

y_{2}=-27

So, the coordinates of V is (7,-27)

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