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3 years ago

Help me please this will help my grade !

Mathematics

1 answer:

saul85 [17]3 years ago

5 0

Answer:

so your answer is C

Step-by-step explanation:

Pi is an irrational number---you can't write it down as a non-infinite decimal. This means you need an approximate value for Pi. The simplest approximation for Pi is just 3

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What is the reciprocal of 2 3/8

Maksim231197 [3]

Basically 0.42105263157

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2 years ago

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(3x^2)^-3y divided by xy

scZoUnD [109]

The number in the photo should be the answer but the problem might just be that your question was worded incorrectly.

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3 years ago

Trash Cans: Elliot's family has a cylinder shaped trash can. It takes the family a few days to fill the trash can up. Elliot wan

Elza [17]

The volume of cylinder shaped trash can is 4698 cubic inches, if the trash can has a height of 24.90 inches and a diameter of 15.50 inches.

Step-by-step explanation:

The given is,

Trash can has a height of 24.90 inches

Diameter of 15.50 inches

Step:1

Formula to calculate the volume of cylinder,

$Volume, V = \pi r^{2} h$ .............................(1)

Where, r - radius of cylinder

h - Height of cylinder

From given,

h - 24.90 inches

D - 15.50 inches

Diameter to radius conversion,

$Radius, r = \frac{d}{2}$

$= \frac{15.50}{2}$

r = 7.75 inches

Equation (1) becomes,

$V = \pi (7.75^{2} )(24.90)$

$= \pi (60.0625)(24.90)$

$=\pi (1495.556)$

$=(3.1416) (1495.556)$ (∵ $\pi = 3.1416$ )

= 4698.42

≅ 4698 cubic inches

Volume of trash can, V = 4698 cubic inches

Result:

The volume of cylinder shaped trash can is 4698 cubic inches, if the trash can has a height of 24.90 inches and a diameter of 15.50 inches.

6 0

3 years ago

Help with 21 would be much appreciated.

umka2103 [35]

Answer:

$\large\boxed{x=2\sqrt{21}\ and\ y=4\sqrt3}$

Step-by-step explanation:

Look at the picture.

ΔADC and ΔCDB are similar. Therefore the sides are in proportion:

$\dfrac{AD}{CD}=\dfrac{CD}{DB}$

We have

$AD=14-8=6\\CD=y\\DB=8$

Substitute:

$\dfrac{6}{y}=\dfrac{y}{8}$ <em>cross multiply</em>

$y^2=(6)(8)$

$y^2=48\to y=\sqrt{48}\\\\y=\sqrt{16\cdot3}\\\\y=\sqrt{16}\ cdot\sqrt3\\\\\boxed{y=4\sqrt3}$

For x use the Pythagorean theorem:

$x^2=6^2+(4\sqrt3)^2\\\\x^2=36+48\\\\x^2=84\to x=\sqrt{84}\\\\x=\sqrt{4\cdot21}\\\\x=\sqrt4\cdot\sqrt{21}\\\\\boxed{x=2\sqrt{21}}$

3 0

3 years ago

The answer is 8 but how do you solve it<br><br> 6-2(3-4)

Neko [114]

Start with the parentheses

3 0

3 years ago

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