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worty [1.4K]
3 years ago
9

The ratio of boys to girls in Mr. Lee's Geography class is 3 to 5. If there are a total of 32 students in the class, how many of

them are girls?
Mathematics
1 answer:
SIZIF [17.4K]3 years ago
5 0
20 are girls (12:20)
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If a train travels 70 miles per hour how long will it take it to travel 350 miles at this speed
svetoff [14.1K]
Since the train travels at a rate of 70 miles/hour, the train will take 5 hours to have traveled a total of 350 miles. The missing information in the question you've proposed is the value of "H" or the number of hours (as the unit hours is indicated in the question). This can be determined with the formula <em>Distance = rate X time. </em>350 = 70 X H, in this case. To isolate the variable H, 70 (the rate) divides 350 (the total distance) into 5. 350 ÷ 70 = H. 5 = H, the amount of time spent traveling for 350 miles at a rate of 70 miles/hour.

4 0
3 years ago
Write in y=mx+b form
DENIUS [597]

Step-by-step explanation:

b =-4 (y-intercept)

x =0

m = 0 (the line doesn't have a slope)

y = mx + c

y = 0(0) + (-4)

y = - 4

7 0
3 years ago
A street light is mounted at the top of a 15-ft-tall pole. A man 6 ft tall walks away from the pole with a speed of 4 ft/s along
mina [271]

Answer:

The tip of the man shadow moves at the rate of \frac{20}{3} ft.sec

Step-by-step explanation:

Let's draw a figure that describes the given situation.

Let "x" be the distance between the man and the pole and "y" be distance between the pole and man's shadows tip point.

Here it forms two similar triangles.

Let's find the distance "y" using proportion.

From the figure, we can form a proportion.

\frac{y - x}{y} = \frac{6}{15}

Cross multiplying, we get

15(y -x) = 6y

15y - 15x = 6y

15y - 6y = 15x

9y = 15x

y = \frac{15x}{9\\} y = \frac{5x}{3}

We need to find rate of change of the shadow. So we need to differentiate y with respect to the time (t).

\frac{dy}{t} = \frac{5}{3} \frac{dx}{dt} ----(1)

We are given \frac{dx}{dt} = 4 ft/sec. Plug in the equation (1), we get

\frac{dy}{dt} = \frac{5}{3} *4 ft/sect\\= \frac{20}{3} ft/sec

Here the distance between the man and the pole 45 ft does not need because we asked to find the how fast the shadow of the man moves.

7 0
3 years ago
I need someone who’s very smart
tino4ka555 [31]

The first one is in the hundredths place, and the second one is in the tenths place.

Hope this helps you! Happy Thanksgiving, here's a turkey!

3 0
4 years ago
Read 2 more answers
Whitney kicks a football off the ground. The height, h , in feet, of the football above the ground after t seconds is given by h
malfutka [58]

Answer:

<em>after 4seconds</em>

Step-by-step explanation:

Given the height, h , in feet, of the football above the ground after t seconds expressed by h ( t ) = − 8 t^2 + 32 t, the height of the ball on the ground is 0feet.

Substitute h(t) = 0 into the expression and calculate t;

h ( t ) = − 8 t^2 + 32 t

0 = − 8 t^2 + 32 t

8t² = 32t

8t = 32

Divide both sides by 8

8t/8 = 32/8

<em>t = 4s</em>

<em>Hence the football hits the ground after 4seconds</em>

5 0
3 years ago
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