Consider point P(x,y) such that P, X and Y are collinear,
As vectors
XP = XO + OZ where O(0,0)
XP = OZ - OX
XP= (x,y) - (-3,3)
XP = (x+3, y-3)
Similarly,
PY = (6-x, -3-y)
But XP= 2^PY
[x+3, y-3] = [2(6-x), 2(-3-y)]
Given both vectors are equal, as they go in the same direction, Solve for x and y accordingly:
x+3 = 12 - 2x
x = 3
y-3 = -6-2y
y = -1
Therefore, P(3,-1)
Answer:
28°
Step-by-step explanation:
You're given that line DE and line FG are parallel and KL and FG are perpendicular. Then you can find out angle ∠BAC by using the vertical angles property: ∠BAC=62°. Then since KL and FG are perpendicular ∠ABC = 90°. So you find the angle ∠BCA by finding the sum of interior angles: 62+90+∠BCA=180, therefore ∠BCA is 28°. Finally, ∠x or ∠JCG = 28 because ∠JCG and ∠BCA are vertical angles and congruent.
Two or more angles whose sum is 180° are called supplementary angles. The measure of the ∠y is 120°.
<h3>What are supplementary angles?</h3>
Two or more angles whose sum is 180° are called supplementary angles. If a straight line is intersected by a line, then there are two angles form on each of the sides of the considered straight line. Those two-two angles are two pairs of supplementary angles. That means, that if supplementary angles are aligned adjacent to each other, their exterior sides will make a straight line.
Given the puck strikes the wall at an angle of 30°, it goes away at the same angle of 30°. Therefore, the measure of angle y can be found using the sum of the angle as a supplementary angle. Thus, we can write,
30° + ∠y + 30° = 180°
60° + ∠y = 180°
∠y = 180° - 60° = 120°
Hence, the measure of the ∠y is 120°.
Learn more about Supplementary Angles:
brainly.com/question/2882938
#SPJ1
First multiply 4 so x is on its own.
5/9 multiplied by 4/1 is 20/9.
20/9 simplifies to 2 and 2/9.
x = 2 and 2/9
Hope this helped, and please mark brainliest! :)
Answer:
sgst
Step-by-step explanation:
