Given:
The figure of a rhombus QRST.
To find:
A. The value of x.
B. The measure of angle RQP.
Solution:
A. We need to find the value of x.
We know that the diagonals of a rhombus are perpendicular bisectors. It means the angles on the intersection of diagonals are right angles.
[Right angle]
Divide both sides by 5.
Therefore, the value of x is 15.
B. We need to find the measure of angle RQP.
From the given figure, it is clear that
Putting , we get
Therefore, the measure of angle RQP is 33 degrees.
Answer:
-five sixths= -5/6
six fifths= 6/5
times= multiplication
so , -5/6 x 6/5 = -1
(both sixes get cancelled and the fives also get cancelled to get -1/1 = -1)
Answer: -2, 0, 1, 3
Step-by-step explanation:
when you multiply -7 and -6 by -5 than add 5 you get a higher number than 25.
when you multiply -2, 0, 1 And 3 by -5 than add 5 you get a lower number than 25.
Answer:
<h3> C. y + 7 = -7(x - 3)</h3>
Step-by-step explanation:
The equation of a line is:
y - y₀ = m(x - x₀)
where <em>m</em> is the slope and <em>(x₀, y₀)</em> is the point which the line passes through
The product of slopes of two perpendicular lines is -1
so if given lines slope is ¹/₇ them:
¹/₇·m = -1
m = -7
(3, -7) ⇒ x₀ = 3, y₀ = -7
Therefore:
y - (-7) = -7(x - 3)
<u> </u><u>y + 7 = -7(x - 3) </u>
