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olchik [2.2K]
2 years ago
7

11.The domain of f(x) is [4, 5, 6]. If f(x) = 3x + 2, what is the range?​

Mathematics
1 answer:
grigory [225]2 years ago
3 0

Answer:

The range of the function is:

Range R = {14, 17, 20}

Step-by-step explanation:

Given the function

f(x) = 3x + 2

We also know that range is the set of values of the dependent variable for which a function is defined.  

In other words,  

  • Range refers to all the possible sets of output values on the y-axis.

We are given that the domain of the function is:

Domain D = {4, 5, 6}

Now,

substituting x = 4 in the function

f(4) = 3(4) + 2

f(4) = 12 + 2

f(4) = 14

substituting x = 5 in the function

f(5) = 3(5) + 2

f(5) = 15 + 2

f(5) = 17

substituting x = 6 in the function

f(6) = 3(6) + 2

f(6) = 18 + 2

f(6) = 20

Thus, we conclude that:

at x = 4, y = 14

at x = 5, y = 17

at x = 6, y = 20

Thus, the range of the function is:

Range R = {14, 17, 20}

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The probability mass function of X is f(x)= 1/6, x 1.2...,6 then find out the value
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  • The total of all potential values for a random variable X, weighted by their relative probabilities, is known as the mean (or expected value E[X]) of that variable.
  • Mean(μ) = 1(1/6) + 2(1/6) + 3(1/6) + 4(1/6) + 5(1/6) + 6(1/6).
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  • Mean(μ) = 21/6
  • Mean(μ) = 3.5
  • The square root of the variance of a random variable, sample, statistical population, data collection, or probability distribution represents its standard deviation. It is denoted by 'σ'.
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  • σ² = [(1² + 2²+ 3² + 4²+ 5²+ 6²)/6] - (3.5)²
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  • σ² = (91/6) - (3.5)²
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  • σ = √2.917
  • Standard deviation (σ) = 1.708

To learn more about variance, visit :

brainly.com/question/14116780

#SPJ9

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