The minimum number of comparisons to find the smallest number from 5 integers is 4.
<h3>How to find the Smallest Integer?</h3>
Let the five numbers be a,b,c,d and e.
Let s be an integer
Comparison 1:
a and b will be compared first and the smaller number of them will be equal to s
Comparison 2:
Now, a smaller number between a and b that is s will be compared with c. Similarly, the smaller number of both numbers will be taken as s in the next comparison.
Comparison 3:
Likewise, s and d will be compared and a smaller number will be taken as s for the next comparison
Comparison 4:
Likewise, s and e will be compared and a smaller number will be taken as s for the next comparison.
After 4th comparison, s will be equal to smallest number of 5 integers.
Thus;
Total comparisons = 4
Therefore, the minimum number of comparisons to find the smallest number from 5 integers is 4.
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9514 1404 393
Answer:
-45, 1, 4, 5, 9
Explanation:
The first argument value, -5, is less than -1, so the first section of the function definition is used. f(-5) = 9(-5) = -45.
The 2nd to 5th argument values are in the interval [-1, 3], so the second section of the function definition is used.
The last argument value, 6, is greater than 3, so the last section of the function definition is used. f(6) = (6 -3)^2 = 9.
Function values are shown in the table attached.