Answer:
yes, triangle DEF is similar to triangle DBC, BC corresponds to EF, and angle DCB corresponds to angle F.
Step-by-step explanation:
Part A: Angle D is congruent to angle D by the reflexive property. Since line BC is parallel to line EF then angle DCB = angle DFE by corresponding angles. Hence triangle DEF is similar to triangle DBS by the AA Similarity Postulate.
Part B: BC corresponds to EF because they are in the same order and the triangles listed DEF and DBC
Part C: Angle DCB corresponds to angle F since they are corresponding angles with the two given parallel lines BC and EF.
Believe it’s 15° B is correct
Answer:
a and b are both 2.82842712474619
Step-by-step explanation:
2.82842712474619 squared x 2 =8 + 8 = 16
Answer:
Some relationships:
Angle FGH + Angle FHG = 90
sin(FGH) = cos(FHG)
cos(FGH) = sin(FHG)
Answer: half pound
Step-by-step explanation: lol