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Marrrta [24]
3 years ago
9

Almonds cost $5 per pound. Cashews cost $2 per pound. Matt purchased

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
7 0

Answer:

B 10 pounds

Step-by-step explanation:

Start with what you know.  You know that almost 5 dollars per pound. and that cashews cost 2 dollars per pound. If there are 10 pounds of cashews, that is 20 dollars worth of cashews.  then if you use your head you will figure out that there are 10 pounds.

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You buy two packages of almonds. One package is 10.47 kg and the other is 8.23 kg. What is the difference?
fomenos

Answer:

2.04 kg

Step-by-step explanation:

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3 years ago
Seven more than the product of 7 and a number
n200080 [17]
Answer:

7 + 7n

Explanation:

Seven more (7 plus) the product of 7 and a number (seven times n) = 7 plus 7n
8 0
2 years ago
Read 2 more answers
Please help i really need it really much
Zanzabum

Answer:

1.5

Step-by-step explanation:

Assuming that you mean that Simon is scaling Logan's build, the scale factor is 1.5.

To find this, you divide Simon's fort height by Logans.

7.5/5 = 1.5.

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3 years ago
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Question 11
torisob [31]

The computation shows that the number of possible ways will be 12.

<h3>How to calculate the value?</h3>

From the information given, Mary has four t-shirts-T₁, T2, T3, and T4, and three pairs of jeans-J1, J2, and J3.

Therefore, the number of possible ways that she can choose her outfit will be:

= 4 × 3 = 12

In conclusion, the correct option is 12.

Learn more about computations on:

brainly.com/question/4658834

#SPJ1

5 0
2 years ago
1. A farmer divided a field into 1-foot by 1-foot sections and tested soil samples from 32 randomly selected sections in the fie
Ad libitum [116K]
Part A

Answers:
Mean = 5.7
Standard Deviation = 0.046

-----------------------

The mean is given to us, which was 5.7, so there's no need to do any work there.

To get the standard deviation of the sample distribution, we divide the given standard deviation s = 0.26 by the square root of the sample size n = 32
So, we get s/sqrt(n) = 0.26/sqrt(32) = 0.0459619 which rounds to 0.046

================================================

Part B

The 95% confidence interval is roughly (3.73, 7.67)
The margin of error expression is z*s/sqrt(n)
The interpretation is that if we generated 100 confidence intervals, then roughly 95% of them will have the mean between 3.73 and 7.67

-----------------------

At 95% confidence, the critical value is z = 1.96 approximately

ME = margin of error
ME = z*s/sqrt(n)
ME = 1.96*5.7/sqrt(32)
ME = 1.974949
The margin of error is roughly 1.974949

The lower and upper boundaries (L and U respectively) are:
L = xbar-ME
L = 5.7-1.974949
L = 3.725051
L = 3.73
and
U = xbar+ME
U = 5.7+1.974949
U = 7.674949
U = 7.67

================================================

Part C

Confidence interval is (5.99, 6.21)
Margin of Error expression is z*s/sqrt(n)
If we generate 100 intervals, then roughly 95 of them will have the mean between 5.99 and 6.21. We are 95% confident that the mean is between those values.

-----------------------

At 95% confidence, the critical value is z = 1.96 approximately

ME = margin of error
ME = z*s/sqrt(n)
ME = 1.96*0.34/sqrt(34)
ME = 0.114286657
The margin of error is roughly 0.114286657

L = lower limit
L = xbar-ME
L = 6.1-0.114286657
L = 5.985713343
L = 5.99

U = upper limit
U = xbar+ME
U = 6.1+0.114286657
U = 6.214286657
U = 6.21
5 0
3 years ago
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