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Nookie1986 [14]
3 years ago
7

Solve for I. 12x + 7 < -11 AND 5.0 – 8 > 40

Mathematics
1 answer:
OLEGan [10]3 years ago
8 0

Answer:

x<3/2

Step-by-step explanation:

12x+7<-11

12x<-11-7

12x<-18

x<-3/2

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A student clamied that the number -4 is not rational because it is not a ratio of two integers. Do you agree or disagree?​
RideAnS [48]

Answer:

I disagree.

Step-by-step explanation:

An integer is a whole number ranging from -2,147,483,648 to 2,147,483,647.

A ratio of two integers with -4 could be -4/1, so -4 is a rational number.

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3 years ago
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Ten times anumber increased by four is no more than twenty-five
Rus_ich [418]
Here is the inequality you are describing: 

10x+4≤25

Where x is the "number" you are describing.
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4 years ago
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What is the slope of the line in this graph?
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<h3>Where is the image of the given graph?</h3>

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8 0
3 years ago
Can someone help me with this
mash [69]

The center of the circle is (h,k) = (-2,-3)

The radius of the circle is r = 2

The standard form of equation of the circle is

{(x + 2)}^{2}  +  {(y + 3)}^{2}  = 4

<h3>How to find the center, radius and standrad form of the circle?</h3>

The general form of equation of the circle is

{(x - h)}^{2}  +  {(y - k)}^{2}  =  {r}^{2}

Here, (h,k) means centre of the circle.

r means radius of the circle.

given that coordinate points of centre of circle is (-2,-3).

Hence the (h,k) = (-2,-3)

<h3>How to find the radius of the circle?</h3>

Now to find the radius of the circle

The distance from a circle's centre to its circumference is its radius.

The distance from a circle's centre (-2,-3) to its circumference (0,-3) is its radius.

using the formula, distance between the two points to obtain radius.

d =  \sqrt{(x1 - x2) {}^{2}  +  {(y1 - y2)}^{2} }  \\ r =  \sqrt{ {( - 2 - 0)}^{2} +  {( - 3 - ( - 3))}^{2}  }  \\ r =  \sqrt{ {( - 2)}^{2} +  {( - 3 + 3)}^{2}  }  \\ r =  \sqrt{ {4}^{2} + 0 }  \\ r =  \sqrt{4}  \\ r = 2

<h3>How to find the standard form of equation of the circle?</h3>

(h,k) = (-2,-3)

r = 2

subtitue the (h,k) and r values to get the standard form of equation of the circle.

(x - h) {}^{2}  +  {(y - k)}^{2}  =  {r}^{2}

{(x - ( - 2))}^{2}  +  {(y - ( - 3))}^{2} =  {r}^{2}

{(x + 2)}^{2}  +  {(y + 3)}^{2}  = 4

Learn more about circle, refer:

brainly.com/question/24810873

#SPJ9

5 0
2 years ago
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cupoosta [38]

Answer:

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3 years ago
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