P/4+=16 Pls show work!!
1 answer:
You might be interested in
Answer: option 1.
x f(x)
4 log (4) 4 = 1 ... because 4^1 = 4
16 log(4) 16 = 2 .... because 4^2 = 16
64 log (4) 64 = 3 .... because 4^3 = 64
x f(x)
4 log (4) 4 = 1 ... because 4^1 = 4
16 log(4) 16 = 2 .... because 4^2 = 16
64 log (4) 64 = 3 .... because 4^3 = 64
Only selections B and D give a maximum height of 13 at t=3. However, both of those functions have the height be -5 at t=0, meaning the ball was served from 5 ft below ground. This does not seem like an appropriate model.
We suspect ...
• the "correct" answers are probably B and D
• whoever wrote the problem wasn't paying attention.
We suspect ...
• the "correct" answers are probably B and D
• whoever wrote the problem wasn't paying attention.